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Mik có sửa lại đề
C1: \(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{3}{7}+\dfrac{3}{14}=\dfrac{6}{14}+\dfrac{3}{14}=\dfrac{9}{14}\)
C2:\(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{6}{7}\times\left(\dfrac{1}{2}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\left(\dfrac{2}{4}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\dfrac{3}{4}=\dfrac{9}{14}\)
\(=\dfrac{3}{7}\times\left(\dfrac{1}{5}+\dfrac{2}{3}-\dfrac{1}{8}\right)\\ =\dfrac{3}{7}\times\left(\dfrac{24}{5\times24}+\dfrac{2\times40}{3\times40}-\dfrac{15}{8\times15}\right)\\ =\dfrac{3}{7}\times\left(\dfrac{24+80-15}{120}\right)\\ =\dfrac{3}{7}\times\dfrac{89}{120}\\ =\dfrac{89}{280}\)
\(\dfrac{3}{7}\times\dfrac{1}{5}+\dfrac{2}{3}\times\dfrac{3}{7}-\dfrac{3}{7}\times\dfrac{1}{8}\)
\(=\dfrac{3}{7}\times\left(\dfrac{1}{5}+\dfrac{3}{7}-\dfrac{1}{8}\right)\)
\(=\dfrac{3}{7}\times\dfrac{56+120-35}{280}\)
\(=\dfrac{3}{7}\times\dfrac{141}{280}\)
\(=\dfrac{423}{1960}\)
6 x5/3=10 7:8/4+1/3=23/6 2x5/8-1/2=3/4 3/7:5/6x1/4=9/70
\(\frac{4}{7}+x=\frac{5}{7}\cdot\frac{1}{2}\)
\(\frac{4}{7}+x=\frac{5}{14}\)
\(x=\frac{5}{14}-\frac{4}{7}\)
\(x=\frac{5}{14}-\frac{8}{14}\)
\(x=-\frac{3}{14}\)
5/6 x 1/7 - 1/7 x 1/6 = \(\dfrac{1}{7}x\left(\dfrac{5}{6}-\dfrac{1}{6}\right)=\dfrac{1}{7}x\dfrac{4}{6}=\dfrac{2}{21}\)
8/15 : 4/5 x 3/2= \(\dfrac{8}{15}x\dfrac{5}{4}x\dfrac{3}{2}=\dfrac{120}{120}=1\)
5/6 x 1/7 - 1/7 x 1/6
= 1/7 x (5/6 - 1/6)
= 1/7 x 2/3
= 2/21
8/15 : 4/5 x 3/2
= 2/3 x 3/2
= 1
a: =1/7(5/6-1/6)=1/7x2/3=2/21
b: =8/15x5/4x3/2=1