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Bài 1:
\(=\dfrac{-3-39}{42}+\dfrac{-6-11}{17}-\dfrac{1}{6}=-\dfrac{119}{48}\)
Bài 2:
=>x:5=-13/20
hay x=-65/20=-13/4
Bài 1:
\(=\dfrac{-3-39}{32}+\dfrac{-6-11}{17}+\dfrac{-1}{6}=-\dfrac{21}{16}+\dfrac{-1}{6}-1=-\dfrac{119}{48}\)
Bài 2:
\(\Leftrightarrow x:5=-\dfrac{13}{20}\)
hay x=-13/4
\(M=\frac{17}{5}\cdot\frac{1}{2}\cdot\frac{10}{17}\cdot\frac{-1}{2^3}\)
\(=\frac{17}{5}\cdot\frac{10}{17}\cdot\frac{1}{2}\cdot\frac{-1}{8}\)
\(=\frac{17\cdot10}{5\cdot17}\cdot\frac{1\cdot(-1)}{2\cdot8}\)
\(=\frac{1\cdot2}{1\cdot1}\cdot\frac{1\cdot(-1)}{2\cdot8}\)
\(=2\cdot\frac{-1}{16}=\frac{2\cdot(-1)}{16}=\frac{1\cdot(-1)}{8}=\frac{-1}{8}\)
\(M=\frac{17}{5}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{2^3}\)
\(\Leftrightarrow M=\frac{17}{5}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{8}\)
\(\Leftrightarrow M=\left(\frac{17}{5}.\frac{10}{17}\right)\left(\frac{1}{2}-\frac{-1}{8}\right)\)
\(\Leftrightarrow M=2.\frac{-1}{16}\)
\(\Leftrightarrow M=\frac{-2}{16}=\frac{-1}{8}\)
\(\dfrac{17}{5}.\dfrac{-31}{125}.\dfrac{1}{2}.\dfrac{10}{17}.\dfrac{-1}{2^3}\\= \left(\dfrac{17}{5}.\dfrac{10}{17}\right)\left(\dfrac{-31}{125}.\dfrac{-1}{8}\right).\dfrac{1}{2}\\ =2.\dfrac{31}{1000}.\dfrac{1}{2}\\ =\left(2.\dfrac{1}{2}\right).\dfrac{31}{1000}\\ =1.\dfrac{31}{1000}\\ =\dfrac{31}{1000}\)
=\(\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{1}{22}-\dfrac{23}{22}\right)+\dfrac{2}{3}\)
=\(\dfrac{17}{17}-\dfrac{22}{22}+\dfrac{2}{3}\)
=\(1-1+\dfrac{2}{3}\)
=0+\(\dfrac{2}{3}\)
=\(\dfrac{2}{3}\)
\(\frac{\frac{4}{17}-\frac{4}{45}+\frac{4}{156}}{\frac{3}{17}-\frac{3}{45}+\frac{3}{156}}=\frac{4.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}{3.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}=\frac{4}{3}\)