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a ) \(5\frac{3}{4}:3+2\frac{1}{4}.\frac{1}{3}-\frac{3}{8}=\frac{23}{4}:\frac{3}{1}+\frac{9}{4}.\frac{1}{3}=\frac{23}{12}+\frac{3}{4}=\frac{8}{3}\)
b ) \(\frac{3}{5}:\frac{5}{6}:\frac{6}{7}:\frac{7}{8}+\frac{7}{8}+\frac{2}{5}+\frac{23}{35}=\frac{3.6.7.8}{5.5.6.7}+\frac{7}{8}+\frac{2}{5}+\frac{23}{35}=\frac{24}{25}+\frac{7}{8}+\frac{2}{5}+\frac{23}{35}=\frac{4049}{1400}\)
\(\frac{6}{7}:\frac{1}{2}.\frac{3}{4}-\frac{5}{8}\)
\(=\frac{6}{7}.2.\frac{3}{4}-\frac{5}{8}\)
\(=\frac{6.2.3}{7.4}-\frac{5}{8}\)
\(=\frac{3.2.2.3}{7.4}-\frac{5}{8}\)
\(=\frac{3.̸4.3}{7.̸4}-\frac{5}{8}\)
\(=\frac{9}{7}-\frac{5}{8}\)
\(=\frac{72}{56}-\frac{35}{56}\)
\(=\frac{37}{56}\)
Rất vui vì giúp đc bạn <3
1/3xD=1/(2x4)+1/(4x6)+...+1/(98x100)
2/3xD=2/(2x4)+2/(4x6)+...+1/(98x100)
2/3xD= 1/2-1/4+1/4-1/6+...+1/98-1/100
2/3xD=1/2-1/100
2/3xD=49/100
D=147/200
\(\frac{1}{8}=12,5\%\) ; \(\frac{1}{16}=6,25\%\) ; \(\frac{1}{2}=50\%\) ; \(\frac{1}{4}=25\%\)
Thay vào trên mà tính.
= \(1+\left(\frac{3\left(1x2+2x4x2\right)}{3\left(5+5x3x25\right)}+1\right)-\left(1+\frac{18}{54}\right)-1\) = \(\frac{18}{380}-\frac{18}{54}\)
\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}\)
\(=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{2}{2}\)
\(=\frac{1}{2}\times4\)
\(=2\)
\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}\)
= \(\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}\)
= \(\frac{1}{2}.4\)
= 2