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1/100-1/100.99-1/99.98-.....1/3.2-1/2.1
= 1/100-(1/100.99+1/99.98+.....+1/3.2+1/2.1)
=1/100-(1/1-1/2+1/2-1/3+...+1/98-1/99+1/99-1/100)
=1/100-(1/1-1/100)
=1/100-99/100
=-98/100
=-49/50
đề :
= 1/100 - (1 / 100.99 +1/99.98 + ...+ 1/3.2 +1/2.1 )
=1/100 - (1 /1.2 +1/ 2.3 +...+ 1/ 98.99 +1 / 99.100)
=1/100 -( 1- 1/ 2 +1/2 -1/3 +...+1/98 -1/99 +1/99 -1/100)
=1/100 - ( 1- 1/100)
=1/100 - 99 /100
= -98/100
= -49 /50
\(A=\frac{1}{100}-\frac{1}{100.99}-\frac{1}{99.98}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
\(=\frac{1}{100}-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(=\frac{1}{100}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(\frac{1}{100}-\left(1-\frac{1}{100}\right)=\frac{1}{100}+\frac{1}{100}-1=\frac{1}{50}-1=-\frac{49}{50}\)
Dễ mà bạn:
a) Cho A=1/100-1/100.99-1/99.98-...-1/3.2-1/2.1
\(A=\frac{1}{100}-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(A=\frac{1}{100}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(A=\frac{1}{100}-\left(1-\frac{1}{100}\right)=\frac{1}{100}-\frac{99}{100}=-\frac{98}{100}=-\frac{49}{50}\)
b) \(-15,5.20,8+3,5.9,2-15,5.9,2+3,5.20,8=-15,5.\left(20,8+9,2\right)+3,5\left(9,2+20,8\right)\)
\(=-15,5.30+3,5.30=30\left(3,5-15,5\right)=30.\left(-12\right)=-360\)
36+(3.23-4.32)
=36+(3.8-4.9)36+(24-36)
=24+(36-36)
=24+0
=24