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1/ 2155-(174+2155)+(-68+174)
=2155-174-2155-68+174
=[2155+(-2155)]+[(-174)+174]+(-68)
=0+0+(-68)
=-68
2/ -25.72+25.21-49.25
=25.(-72)+25.21-49.25
=25.[(-72)+21+(-49)]
=25.(-100)
=-2500
3/ 35.(14-23)-23.(14-45)
=35.14-35.23-23.14-23.45
=(35.14-23.14)+(-35.23-23.45)
=(35.14-23.14)+(-35.23-45.23)
=14.(35-23)+23.(-35-45)
=14.12+23.(-80)
=168+(-1840)
=-1672
4/ 8154-(674+8154)+(-98+674)
=8154-674-8154-98+674
=[8154+(-8154)]+[(-674)+674]+(-98)
=0+0+(-98)
=-98
5/ -25.21+25.72+49.25
=-12.25+25.72+49.25
=25.(-12+72+49)
=25.109
=2725
Đúng thì chọn đúng cho mình nhé !
1135/23-167/32+330/23
=(1135/23-330/23)+167/32
=805/23+167/32
=35+167/32
=1120/32+167/32
=1287/32
A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
=\(\frac{1135}{32}-\left(\frac{167}{32}+\frac{330}{23}\right)\)
=\(\frac{1135}{23}-\frac{167}{32}-\frac{330}{23}\)
=\(\left(\frac{1135}{23}-\frac{330}{23}\right)-\frac{167}{32}\)
=\(\frac{805}{23}-\frac{167}{32}\)
=\(\frac{953}{32}\)
\(a.23.\left(75+25\right)+127.100\)
\(23.100+127.100\)
\(100.\left(127+23\right)\)
\(100.150\)
\(15000\)
\(b.\left(20+30\right)+\left(21+29\right)+22\)
\(50+50+22\)
\(100+22=122\)
\(23.75+25+23+127.100\)
\(=1725+25+23+12700\)
\(=1750+23+12700\)
\(=1773+12700\)
\(=14473\)
\(20+21+22+29+30\)
\(=\left(20+30\right)+\left(21+29\right)+22\)
\(=50+50+22\)
\(=50.2+22\)
\(=100+22\)
\(=122\)
\(a,-35.12-8.35\)
\(=\left(-35\right)\left(12+8\right)\)
\(=-700\)
\(b,-23.7-7.59-18.7\)
\(=7\left(-23-59-18\right)\)
\(7.\left(-100\right)=-700\)
\(b,115-\left(-12+29\right)\)
\(=115+12-29\)
\(=98\)
\(c,3.\left(-7\right)^2+5.\left(-4\right)^3\)
\(=3.49-5.64\)
\(=147-320\)
\(=-173\)
a)-35.12-8-35=-35(12+8)=-35.20=-700
b)23.(-7)-7.5+(-18).7=-7(23+59+18)=-7.100=-700
c)115-(-12+29)=115+12-29=98
d)\(3\left(-7\right)^2+5\left(-4\right)^3=3.7^2-5.4^3=3.49-5.64=147-320-173\)
a) (-21) + |-50| + (-29) – |-2016|
= (-21) + 50 + (-29) – 2016
= [(-21) + (-29) + 50] – 2016 = ( -50 +50 ) – 2016
= 0 – 2016 = - 2016 .
b) 36 : 3 2 + 3 2 . 2 3 - 15 0
= 36 : 9 + 9 . 8 – 1 = 4 + 72 – 1 = 76 – 1 = 75
c) ( 5 103 – 5 102 – 5 101 ) : ( 5 99 . 26 – 5 99 )
= ( 5 103 – 5 102 – 5 101 ) : 5 99 . ( 26 – 1 )
= ( 5 103 – 5 102 – 5 101 ) : ( 5 99 . 25 )
= 5 101 ( 5 2 – 5 1 – 5 0 ) : ( 5 99 . 5 2 )
= ( 5 101 . 19 ) : 5 101 = 19
A=\(\frac{\left(1+29\right)\left[\left(29-1\right):2+1\right]:2}{\left(49+21\right)\left[\left(49-21\right):2+1\right]:2}\)
A=\(\frac{30.15:2}{70.15:2}\)
A=\(\frac{30:2}{70:2}\)
A=\(\frac{15}{35}\)
A=\(\frac{3}{7}\)
Vậy A=\(\frac{3}{7}\)
A=1/2