Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{1616}{1717}\right)\)
\(=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16}{17}\right)\)
\(=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)
\(=\left(\frac{15}{16}-\frac{15}{16}\right)+\left(\frac{1}{17}+\frac{16}{17}\right)\)
\(=\frac{15-15}{16}+\frac{1+16}{17}\)
\(=0+\frac{17}{17}\)
\(=0+1\)
\(=1\)
mk cũng đang làm có gì bạn nhận được câu trả lời nhắn tin cho mk vs
C=(15/16+1/17)-(15/16-176/187)
C=15/16+1/17-15/16+176/187
C=[15/16+(-15/16)]-[1/17+176/187]
ban lam tiep nhe
=\(\left(\frac{15}{16}+\frac{1}{17^5}\right)+\left(\frac{16}{17}-\frac{15}{16}\right)\)
=\(\frac{1}{17^5}+\frac{16}{17}=\frac{1+16.17^4}{17^5}\)
đáp số là số thập phân vô hạn không tuần hoàn
\(B=\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{176}{187}\right)\)
\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16}{17}\right)\)
\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)
\(B=\left(\frac{15}{16}-\frac{15}{16}\right)+\left(\frac{1}{17}+\frac{16}{17}\right)\)
\(B=0+1=1\)
Vậy: B=1
\(\dfrac{151515}{161616}+\dfrac{1}{17}-\dfrac{1500}{1600}-\dfrac{16}{17}\)
\(=\dfrac{10101.15}{10101.16}+\dfrac{1}{17}-\dfrac{15.100}{16.100}-\dfrac{16}{17}\)
\(=\dfrac{15}{16}+\dfrac{1}{17}-\dfrac{15}{16}-\dfrac{16}{17}=\dfrac{-15}{17}\)
\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16.11}{17.11}\right)\)
\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)
\(B=\frac{1}{17}+\frac{16}{17}=\frac{17}{17}=1\)
\(\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{1616}{1717}\right)\)
\(=\left(\frac{15.10101}{16.10101}+\frac{1}{17}\right)-\left(\frac{15.100}{16.100}-\frac{16.101}{17.101}\right)\)
\(=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}=\frac{1}{17}+\frac{16}{17}=\frac{17}{17}=1\)