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Như vậy kết quả sẽ nhỏ hơn đấy
a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)
\(\frac{4}{5}+\frac{2}{35}\times\frac{7}{2}=\frac{4}{5}+\frac{1}{5}=1\)
\(\frac{4}{5}+\left(\frac{1}{5}-\frac{1}{7}\right):\frac{2}{7}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\frac{1}{7}:\frac{2}{7}\)
\(=\frac{5}{5}-\frac{1}{2}\)
\(=1-\frac{1}{2}=\frac{1}{2}\)
\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)
\(=\left(\frac{19}{15}-\frac{4}{15}\right)+\left(\frac{31}{23}-\frac{8}{23}\right)\)
\(=\frac{15}{15}+\frac{23}{23}\)
\(=1+1=2\)
\(\frac{19}{15}+\frac{31}{23}-\frac{14}{15}-\frac{8}{23}\)
\(=\frac{19}{15}-\frac{4}{15}+\frac{31}{23}-\frac{8}{23}\)
\(=1+1=2\)
chúc bạn học giỏi
\(\frac{7}{15}+\frac{9}{16}+\frac{8}{15}+\frac{7}{16}\)
= \(\left(\frac{7}{15}+\frac{8}{15}\right)+\left(\frac{9}{16}+\frac{7}{16}\right)\)
= \(\frac{15}{15}+\frac{16}{16}\)
= 1+1
= 2
a, \(\frac{5}{11}\times\frac{7}{25}+\frac{15}{11}\times\frac{1}{5}\)
\(=\frac{5}{11}\times\frac{7}{25}+\frac{5}{11}\times\frac{3}{5}\)
\(=\frac{5}{11}\times\left(\frac{7}{25}+\frac{3}{5}\right)\)
\(=\frac{5}{11}\times\frac{22}{25}\)
\(=\frac{2}{5}\)
b, \(\frac{3}{7}\times\frac{25}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\frac{75}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\left(\frac{75}{19}-\frac{18}{19}\right)\)
\(=\frac{1}{7}\times3\)
\(=\frac{3}{7}\)
\(\frac{8}{15}:\frac{2}{11}+\frac{7}{15}:\frac{2}{11}\)
\(=\left(\frac{8}{15}+\frac{7}{15}\right):\frac{2}{11}\)
\(=1:\frac{2}{11}\)
\(=\frac{11}{2}\)
a) 18/15 + 7/15+12/15 = 18/15 + 12/15 +7/15
= 30/15+ 7/15
= 37/15
b) 9/7+8/7 + 11/7 = 9/7 + 11/7 + 8/7
= 20/7 + 8/7
= 28/7
a) \(\frac{18}{15}+\frac{7}{15}+\frac{12}{15}=\frac{18}{15}+\frac{12}{15}+\frac{7}{15}=\frac{30}{15}+\frac{7}{15}\)\(=\frac{37}{15}\)
b)\(\frac{9}{7}+\frac{8}{7}+\frac{11}{7}=\frac{9}{7}+\frac{11}{7}+\frac{8}{7}=\)\(\frac{20}{7}+\frac{8}{7}=\frac{28}{7}\)
\(\frac{15}{4}-\frac{1}{7}-\frac{6}{7}\)
\(=\frac{15}{4}-\left(\frac{1}{7}+\frac{6}{7}\right)\)
\(=\frac{15}{4}-\frac{7}{7}\)
\(=\frac{15}{4}-1\)
\(=\frac{15}{4}-\frac{4}{4}\)
\(=\frac{11}{4}\)
\(\frac{15}{4}-\frac{1}{7}-\frac{6}{7}\)
\(=\frac{15}{4}-\left(\frac{1}{7}+\frac{6}{7}\right)\)
\(=\frac{15}{4}-\frac{7}{7}\)
\(=\frac{15}{4}-1\)
\(=\frac{15}{4}-1\)
\(=\frac{15}{4}-\frac{4}{4}\)
\(=\frac{11}{4}\)