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127,15 x 3 + 127,15 x 9 - 127,15 - 127,15
= 127,15 x 3 + 127,15 x 9 - 127,15 x 1 - 127,15 x 1
=127,15 x ( 3+9-1-1)
=127,15 x 10
=1271,5
Bài 1:
a) Ta có: \(2\cdot4\cdot5\cdot25\cdot28\)
\(=\left(2\cdot5\right)\cdot\left(4\cdot25\right)\cdot28\)
\(=10\cdot100\cdot28\)
=28000
b) Ta có: \(45\cdot54+45\cdot23-35\cdot77\)
\(=45\left(54+23\right)-35\cdot77\)
\(=45\cdot77-35\cdot77\)
=770
1/Tính nhanh
a) 2.4.5.25.28
= (2.5) . (4.25) . 28
= 10 . 100 . 28
= 1000 . 28
= 28000
b) 45.54+45.23-35.77
= 45.(54 + 23) - 35.77
= 45.77 - 35.77
= (45 -35) . 77
= 10 . 77
= 770
2/Tìm x:
6.x + 108 : 9 = 24
6.x + 12 = 24
6.x = 24 - 12
6.x = 12
x = 12 :6
x = 2
Vậy x=2
*Dấu chấm là dấu nhân nha *
1/5 + 1/45 + 1/117 msc : 585 1/117 = 5/585 1/45 = 13/ 585 1/5 = 117 / 585
135 / 585 = 3 / 13
\(\Rightarrow\frac{1}{1}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{13}=\frac{12}{13}\)
Nếu thấy ai làm theo mk thì bn đừng k nhé
75/100 + 3/4 x 29 + 75% x 30 + 0,75 x 40
= 0,75 + 0,75 x 29 + 0,75 x30 + 0,75 x 40
= 0,75 x ( 1 + 29 + 30 + 40 )
= 0,75 x 100
=75
\(\frac{75}{100}+\frac{3}{4}\times29+75\%\times30+0,75\times40\)
\(=\frac{75}{100}\times1+\frac{3\times25}{4\times25}\times29+\frac{75}{100}\times30+\frac{0,75}{1}\times40\)
\(=\frac{75}{100}\times1+\frac{75}{100}\times29+\frac{75}{100}\times30+\frac{0,75\times100}{1\times100}\times40\)
\(=\frac{75}{100}\times1+\frac{75}{100}\times29+\frac{75}{100}\times30+\frac{75}{100}\times40\)
\(=\frac{75}{100}\left(1+29+30+40\right)\)
\(=\frac{75}{100}\times100\)
\(=\frac{75}{100}\times\frac{100}{1}\)
\(=\frac{75}{1}\)
\(=75\)
\(=\frac{75\times100}{100\times1}\)
2 x 3 x 4 x 8 x 50 x 25 x 125
= 3 x 2 x 4 x 50 x 8 x 25 x 125
= 3 x (2 x 50) x (4 x 25) x (8 x 125)
= 30 000 000.
18 x 32,7 + 3 x 51,2 x 6 + 9 x 2 x 16,1
= 18 x 32,7 + (6 x 3) x 51,2 + (9 x 2) x 16,1
= 18 x 32,7 + 18 x 51,2 + 18 x 16,1
= 18 x (32,7 + 51,2 + 16,1)
= 18 x 100
= 1800
`18xx32,7+3xx51,2xx6+9xx2xx16,1`
`=18xx32,7+18xx51,2+18xx16,1`
`=18xx(32,7+51,2+16,1)`
`=18xx100`
`=1800`
`18xx32,7+3xx51,2xx6+9xx2xx16,1`
`=18xx32,7+18xx51,2+18xx16,1`
`=18xx(32,7+51,2+16,1)`
`=18xx100`
`=1800`
a) (3 + 6 + 9 + ... + 303) x (245 - 49 x 5)
(3 + 6 + 9 + ... + 303) x (245 - 245)
(3 + 6 + 9 + ... + 303) x 0 = 0
= 127,15 x3 +127,15 x 9 -127,15 x 1-127,15 x1
= 127,15 x ( 9+3 -1 -1 )
= 127,15 x 10
= 1271,5