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1+2+3+4+5+6
= (1+6) x 3
= 7 x 3
= 21
11+22+33+44+55+66
= (11+66) x 3
= 77 x 3
= 231
a 3*5*6*8*9/6*9*10*4*3=(3/3)*(5/10)*(6/6)*(9/9)*(8/4)=1*1/2*1*1*2=1
b 15*18*20*22/3*5*9*2*11*40=(15/3/5)*(18/9/2)*(20/40)*(22/11)=1*1*1/2*2=1
Bài 2:
a: 2/6x5/3=10/18=5/9
b: 11/9x5/10=55/90=11/18
c: 3/9x6/8=1/3x3/4=1/4
d: 4/9x12/16=48/144=1/3
e: 25/15x6/7=5/3x6/7=30/21=10/7
f: 6/10x15/20=90/200=9/20
Bài 1
4/5 x 6/7= 24/35
2/9 x 1/2= 2/18= 1/9
1/2 x 8/3= 8/6= 4/3
7/9 x 6/5= 42/45= 14/15
8/7 x 5/9= 40/63
10/11 x 22/15= 220/165= 4/3
Bài 2
2/6 x 5/3= 1/3 x 5/3=5/9
11/9 x 5/10= 11/9 x 1/2= 11/18
3/9 x 6/8= 1/3 x 3/4 =3/12= 1/4
4/9 x 12/16= 4/9 x 3/4= 12/36= 1/3
25/15 x 6/7= 5/3 x 6/7= 30/21= 10/7
6/10 x 15/20= 3/5 x 3/4= 9/20
a, \(\dfrac{5\times11\times15\times18}{6\times15\times22\times10}\)
= \(\dfrac{5\times11\times15\times6\times3}{6\times15\times11\times2\times2\times5}\)
= \(\dfrac{5\times11\times15\times6}{5\times11\times15\times6}\) \(\times\) \(\dfrac{3}{2\times2}\)
= 1 \(\times\) \(\dfrac{3}{4}\)
= \(\dfrac{3}{4}\)
b, \(\dfrac{7}{12}\) \(\times\) \(\dfrac{3}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{12}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{7}{12}+\dfrac{5}{12}\))
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{12}{12}\)
= \(\dfrac{3}{5}\) \(\times\) 1
= \(\dfrac{3}{5}\)
a) 1/3 + 3/4 - 7/12
= 4/12 + 9/12 - 7/12
= 6/12
= 1/2
b) 6/11 : 5/22 - 4/5
= 6/11 * 22/5 - 4/5
= 12/5 - 4/5
= 8/5
c) 5/18 * 8
= 40/18
= 20/9
d) 7/15 : 5
= 7/15 * 1/5
= 7/75
OK
a, \(\frac{1}{3}+\frac{3}{4}-\frac{7}{12}\)
= \(\frac{13}{12}-\frac{7}{12}\)
= \(\frac{1}{2}\)
\(b,\frac{6}{11}:\frac{5}{22}-\frac{4}{5}\)
= \(\frac{12}{5}-\frac{4}{5}\)
\(=\frac{8}{5}\)
\(c,\frac{5}{18}x8\)
=\(\frac{20}{9}\)
\(d,\frac{7}{15}:5\)
= \(\frac{7}{15}x\)\(\frac{1}{5}\)
\(=\frac{7}{75}\)
a) \(\dfrac{2}{3}+\dfrac{4}{9}=\dfrac{6}{9}+\dfrac{4}{9}+\dfrac{6+3}{9}=\dfrac{10}{9}\)
b)\(\dfrac{1}{10}+\dfrac{2}{5}=\dfrac{1}{10}+\dfrac{4}{10}=\dfrac{1+4}{10}=\dfrac{5}{10}=\dfrac{1}{2}\)
c) \(\dfrac{7}{22}-\dfrac{3}{11}=\dfrac{7}{22}-\dfrac{6}{22}=\dfrac{7-6}{22}=\dfrac{1}{22}\)
d) \(\dfrac{5}{6}-\dfrac{5}{12}=\dfrac{10}{12}-\dfrac{5}{12}=\dfrac{10-5}{12}=\dfrac{5}{12}\)
