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\(\dfrac{5}{8}\times\dfrac{20}{9}-\dfrac{5}{8}\times\dfrac{7}{9}+1\)
\(=\dfrac{5}{8}\times\left(\dfrac{20}{9}-\dfrac{7}{9}\right)+1\)
\(=\dfrac{5}{8}\times\dfrac{13}{9}+1\)
\(=\dfrac{65}{72}\)
Ta có: \(\dfrac{5}{8}=\dfrac{45}{72}\)
Mà: \(65>45\)
Vậy: \(\dfrac{65}{72}>\dfrac{45}{72}\) hay \(\dfrac{5}{8}\times\dfrac{20}{9}+\dfrac{5}{8}\times\dfrac{7}{9}+1>\dfrac{5}{8}\)
\(\frac{8x15+16x4-8x21}{16x5-8x7}\)
\(\Rightarrow=\frac{120+64-168}{80-56}=\frac{16}{24}=\frac{2}{3}\)
Ủng hộ đi nhen
\(\frac{8\times25+16\times4-8\times21}{16\times5-8\times7}\)
\(\Rightarrow\frac{120+64-168}{80-56}\)
\(\Rightarrow\frac{16}{24}=\frac{2}{3}\)
\(\dfrac{7}{2}\times\dfrac{3}{4}+\dfrac{17}{8}\times\dfrac{2}{3}+\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{7}{8}\times\dfrac{3}{3}\)
\(=\dfrac{7\times3}{2\times4}+\dfrac{17\times2}{8\times3}+\dfrac{3\times1}{4\times2}+\dfrac{7}{8}\times1\)
\(=\dfrac{21}{8}+\dfrac{17}{12}+\dfrac{3}{8}+\dfrac{7}{8}\)
\(=\left(\dfrac{21}{8}+\dfrac{3}{8}+\dfrac{7}{8}\right)+\dfrac{17}{12}\)
\(=\dfrac{31}{8}+\dfrac{17}{12}\)
\(=\dfrac{31\times3}{8\times3}+\dfrac{17\times2}{12\times2}\)
\(=\dfrac{93}{24}+\dfrac{34}{24}\)
\(=\dfrac{127}{24}\)
\(500X1000:1+0X0\)
\(=500000:1+0\)
\(=500000+0\)
\(=500000\)
a)\(\left(\dfrac{5}{6}+\dfrac{3}{8}\right)\times\dfrac{2}{7}\)
\(=\dfrac{29}{24}\times\dfrac{2}{7}\)
\(=\) \(\dfrac{29}{84}\)
b) \(\dfrac{6}{7}\times\dfrac{2}{3}\div\dfrac{5}{7}\)
= \(\dfrac{4}{7}\div\) \(\dfrac{5}{7}\)
= \(\dfrac{4}{5}\)
c) \(\dfrac{8}{9}+\dfrac{3}{4}\times\dfrac{4}{9}\)
= \(\dfrac{8}{9}+\dfrac{1}{3}\)
= \(\dfrac{5}{9}\)
Cô tích xanh cho lisa blackpink vì câu a, b đúng. Còn câu c thì em làm như sau:
c, \(\dfrac{8}{9}\) + \(\dfrac{3}{4}\) \(\times\) \(\dfrac{4}{9}\)
= \(\dfrac{8}{9}\) + \(\dfrac{1}{3}\)
= \(\dfrac{8}{9}\) + \(\dfrac{3}{9}\)
= \(\dfrac{11}{9}\)
a ) 3 + 6 : 9
= ( 3 + 6 ) : 9
= 9 : 9
= 1
b ) 8 +8 x 7 + 8 x 2 + 0 x 0 = 0
Tính :
a)3+6:9
=3+0,666...
=3,666...
b)8+8x7+8x2+0x0
=8+56+16+0
=80