Question

[Linh Tuyết]

Tính 

(1-1/2018) x (1-1/2019) x (1-1/2020) x (1-1/2021) x (1-1/2022)

Answer 1

[Kiyotaka Ayanokoji]

\(\left(1-\frac{1}{2018}\right)\times\left(1-\frac{1}{2019}\right)\times\left(1-\frac{1}{2020}\right)\times\left(1-\frac{1}{2021}\right)\times\left(1-\frac{1}{2022}\right)\)

\(=\frac{2017}{2018}\times\frac{2018}{2019}\times\frac{2019}{2020}\times\frac{2020}{2021}\times\frac{2021}{2022}\)

\(=\frac{2017}{2022}\)