Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
125 : 5^2 . (x-3) = 3
125 : 25 .(x-3) = 3
5 (x-3) =3
x-3 = 3 : 5
Đề bài sai hay sao ý?
2x -5 = 3
2x = 3+5 =8
x =4
(19 .x+2.5^2 ): 14 = (13-8)^2 - 4^2
19x + 50) : 14 = 25 - 16
(19x+50) : 14 = 9
19x+50 = 3*14 = 126
19x = 126-50 = 76
x = 76 / 19 = 4
\(a\)) \(125:5^2.\left(x-3\right)=3\)
\(5^3:5^2.\left(x-3\right)=3\)
\(5.\left(x-3\right)=3\)
\(5x-15=3\)
\(5x=3+15\)
\(5x=18\)
\(x=\frac{18}{5}\)\(.\)Vậy \(x=\frac{18}{5}\)
\(b\)) \(\left(2x-5\right)^3=27\)
\(\left(2x-5\right)^3=3^3\)
\(\Rightarrow2x-5=3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)\(.\)Vậy \(x=4\)
\(c\))\(\left(19.x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19.x+2.25\right):14=5^2-16\)
\(\left(19.x+2.25\right):14=25-16\)
\(\left(19.x+50\right):14=9\)
\(19.x+50=126\)
\(19.x=126-50\)
\(19.x=76\)
\(x=76:19\)
\(x=4\)\(.\)Vậy \(x=4\)
câu b sai rồi,thế này mới đúng nè:
b,(19x+2.55):4=(13-8)2-42
(19x+2.52):14=52-42
(19x+2.52):14=8
19x+2.52+126
19x+50=126
19x=76
x=4
a) [( 6.x-72):2-84].28(thiếu đề)
b) (19.x + 2.52) :14= (13-8)2 - 4
(19.x + 2.25) :14= 5.2 - 4
(19.x + 50) :14=10- 4
(19.x + 50) :14=6
19.x + 50=6.14
19.x +50=84
19.x=84-50
19.x=34
x=34:19
x=34/19
a) ( 19.x + 2.52) : 14 = ( 13 - 8 )2 - 42
(19.x + 2.52) : 14 = 52 - 42
(19.x + 2.25) : 14 = 25 - 16
(19.x + 2.25) : 14 = 9
19.x + 2.25 = 9.14
19.x + 50 = 126
19.x = 126 - 50
19.x = 76
x = 76 : 19
x = 4
Vậy x = 4.
b) mk thấy x ko có já trị nào hết
c) (x - 1)10 = 1
=> (x - 1)10 = 110
=> x - 1 = 1
x = 1 + 1
x = 2
vậy x = 2
\(a.\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=25-16\)
\(\Leftrightarrow\left(19x+50\right):14=9\)
\(\Leftrightarrow19x+50=126\)
\(\Leftrightarrow19x=76\)
\(\Leftrightarrow x=4\)
\(b.\left(x-10\right):2=5-2\left(x+1\right)\)
\(\Leftrightarrow\left(x-10\right):2=5-2x-2\)
\(\Leftrightarrow\frac{1}{2}x-5=3-2x\)
\(\Leftrightarrow\frac{1}{2}x+2x=3+5\)
\(\Leftrightarrow\frac{5}{2}x=8\)
\(\Leftrightarrow x=3,2\)
4.2x-3=125
4.2x=125+3
4.2x=128
2x = 128:4
2x = 32
2x = 25
=> x = 5 ; Vậy x \(\varepsilon\) {5}
(19x+2.52):14=(13-8)2-42
(19x+2.52):14=52-42
(19x+2.52):14=25-16
(19x+2.52):14=9
19x+2.52=9.14
19x+2.52=126
19x+2.25=126
19x+50=126
19x=126-50
19x=76
19x=0 ;Vậy x \(\varepsilon\) {\(\phi\)}