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![](https://rs.olm.vn/images/avt/0.png?1311)
2,
a) \(315-\left(135-x\right)=215\)
\(\Rightarrow135-x=315-215\)
\(\Rightarrow135-x=100\)
\(\Rightarrow x=135-100\)
\(\Rightarrow x=35\)
b) \(x-320:32=25\cdot16\)
\(\Rightarrow x-10=5^2\cdot4^2\)
\(\Rightarrow x-10=20^2\)
\(\Rightarrow x-10=400\)
\(\Rightarrow x=410\)
c) \(3\cdot x-2018:2=23\)
\(=3\cdot x-1009=23\)
\(\Rightarrow3\cdot x=1032\)
\(\Rightarrow x=1032:3\)
\(\Rightarrow x=344\)
d) \(280-9\cdot x-x=80\)
\(\Rightarrow280-x\cdot\left(9+1\right)=80\)
\(\Rightarrow280-10\cdot x=80\)
\(\Rightarrow10\cdot x=280-80\)
\(\Rightarrow10\cdot x=200\)
\(\Rightarrow x=20\)
e) \(38\cdot x-12\cdot x-x\cdot16=40\)
\(\Rightarrow x\cdot\left(38-12-16\right)=40\)
\(\Rightarrow x\cdot10=40\)
\(\Rightarrow x=40:10\)
\(\Rightarrow x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) x = 43 30 x = − 43 30 ; b ) x = 3 2 x = 7 6 . c ) x = 13 6 x = 1 2
d ) x = − 94 45 x = 164 45 ; e ) x = 7 8 x = − 3 8 . f ) x = 7 8 x = − 3 8
![](https://rs.olm.vn/images/avt/0.png?1311)
a)25+(`15-x)=30
15-x=25-30
x=15-5
x=10
b)43-(24-x)=20
24-x=43-20
x=24-23
x=1
c)2.(x-50-17=25
2.(x-5)=25+17
x-5=42:2
x=21+5
x=26
d)3.(x+7)-15=27
3.(x+7)=15+27
x+7=42:3
x=14-7
x=7
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.
![](https://rs.olm.vn/images/avt/0.png?1311)
a)x-13=-5+8
x-13=3
x=3+13
x=16 hoặc -10
b)|x-2|=|-5|
|x-2|=5|
|x|=5+2
|x|=7
x=7 hoặc -7
c)25-(30+x)=x-(27-8)
25-(30+x)=x-19
...còn lại mình bó tay
d)bó tay luôn
a) x-(-25+x)=13-x
⇒ x+25-x=13-x
⇒ 13-x=25
⇒ x= -12
b) 15-(30+x)=x-(27-l-8l)
⇒ 15-30-x=x-(27-8)
⇒ -15-x=x-19
⇒ -x-x=-19+15
⇒ -2x+4=0
⇒ -2x=-4
⇒ x=2
c) (12x-43).83=4.84
⇒ 12x.83-43.83=4.84
⇒ 6144x-32768=16384
⇒ 6144x=49152
⇒ x=8
a: Ta có: \(x-\left(-25+x\right)=13-x\)
\(\Leftrightarrow13-x=25\)
hay x=-12
b: Ta có: \(15-\left(30+x\right)=x-\left(27-\left|-8\right|\right)\)
\(\Leftrightarrow-15-x=x-19\)
\(\Leftrightarrow-2x=-4\)
hay x=2
c: Ta có: \(\left(12x-4^3\right)\cdot8^3=4\cdot8^4\)
\(\Leftrightarrow\left(12x-64\right)\cdot512=16384\)
\(\Leftrightarrow12x-64=32\)
hay x=8