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#)Giải :
a)\(\left(x-149\right)\div35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9599\)
\(a,(x-149):35=270\)
\(\Leftrightarrow x-149=9450\)
\(\Leftrightarrow x=9450+149=9599\)
Vậy x = 9599
\(b,(2009-x):29+32=100\)
\(\Leftrightarrow(2009-x):29=68\)
\(\Leftrightarrow2009-x=1972\)
\(\Leftrightarrow x=2009-1972=37\)
Vậy x = 37
\(c,x+472=918\)
\(\Leftrightarrow x=918-472=446\)
Vậy x = 446
(2009-x) : 29 + 32 = 100
(2009-x): 29 = 68
2009-x = 68 x 29
2009 - x = 2001
x= 2009 - 2001
x=8
( 2009 - x ) : 29 + 32 = 100
( 2009 - x ) : 29 = 100 - 32
( 2009 - x ) : 29 = 68
2009 - x = 68 x 29
2009 - x = 1972
x = 2009 - 1972
x = 37
\(180-\left(x-45\right)\div2=120\)
\(\left(x-45\right)\div2=180-120\)
\(\left(x-45\right)\div2=60\)
\(x-45=60\times2\)
\(x-45=120\)
\(x=120+45\)
\(x=165\)
\(\left(2009-x\right)\div29+32=100\)
\(\left(2009-x\right)\div29=100-32\)
\(\left(2009-x\right)\div29=68\)
\(2009-x=68\times29\)
\(2009-x=1972\)
\(x=2009-1972\)
\(x=37\)
\(\left(x-2\right)\times3-270\div45=120\)
\(\left(x-2\right)\times3-6=120\)
\(\left(x-2\right)\times3=120+6\)
\(\left(x-2\right)\times3 =126\)
\(x-2=126\div3\)
\(x-2=42\)
\(x=42+2\)
\(x=44\)
\(\left(x+0,2\right)+\left(x+0,7\right)+\left(x+1,2\right)+...+\left(x+4,2\right)+\left(x+4,7\right)=65,5\)
\(\left(x+x+x+..+x+x\right)+\left(0,2+0,7+1,2+...+4,2+4,7\right)=65,5\)
\(10x+\frac{\left(0,2+4,7\right)\times10}{2}=65,5\)
\(10x+24,5=65,5\)
\(10x=65,5-24,5\)
\(10x=41\)
\(\Rightarrow x=4,1\)
a) \(7.x+8.x+9.x+...+100.x=1025\)
\(\left(7+8+9+...+100\right).x=1025\)
\(5029.x=1025\)
\(x=1025\div5029\)
\(x=\frac{1025}{5029}\)
b) \(32.\left(x-3\right)+18.x=2\)
\(32.x-32.3+18.x=2\)
\(\left(32+18\right).x-96=2\)
\(50.x=98\)
\(x=98\div50\)
\(x=1,96\)
Chú ý nè: Dấu "." là dấu nhân đó!
a) 7.x+8.x+9.x+...+100.x=1025
(7+8+9+...+100).x=1025
5029.x=1025
x=1025÷5029
x=\(\frac{1025}{5029}\)
\(\dfrac{x-25-124}{2015}\) + \(\dfrac{x-124-2015}{25}\) + \(\dfrac{x-2015-25}{124}\) = 3
\(\dfrac{x-15-124}{2015}\) - 1 + \(\dfrac{x-124-2015}{25}\) - 1 + \(\dfrac{x-2015-25}{124}\) - 1 = 0
\(\dfrac{x-15-124-2015}{2015}\)+\(\dfrac{x-124-2015-25}{25}\)+\(\dfrac{x-2015-25-124}{124}\) = 0
\(\dfrac{x-\left(15+124+2015\right)}{2015}\)+\(\dfrac{x-\left(124+2015+25\right)}{25}\)+\(\dfrac{x-\left(2015+25+124\right)}{124}\) = 0
(\(x\) - 2164).(\(\dfrac{1}{2015}\)+\(\dfrac{1}{25}\)+\(\dfrac{1}{124}\)) = 0
\(x-2164\) = 0
\(x\) = 2164
A=$\frac{2013.\left(2014+1\right)+100}{\left(2013+1\right).2014+99}=\frac{2013.2014+2013+100}{2013.2014+2014+99}$=$\frac{2013.2014+2013+1+99}{2013.2014+2013+1+99}=1$(dấu chấm là dấu nhân nhé)
Mai Trung Kiên ơi,bạn có thể làm hộ mình con c) dc ko?
c] 7 * x + 8 * x + 9 * x + .... + 100 * x = 1025
(7+8+9+...+100)*x=1025
Coi A= 7+8+...+100
Số các số hạng của A là:
(100-7):1+1=94 (số)
=>A=(100+7)*94:2=5029
Ta lại có:
5029*x=1025
=>x=1025:5019=1025/5019
a, \(x.\left(\frac{3}{2}+\frac{1}{4}-\frac{1}{2}\right)=x.\left(\frac{6}{4}+\frac{1}{4}-\frac{2}{4}\right)=\frac{10}{9}\)
\(x.\frac{5}{4}=\frac{10}{9}\)
\(x=\frac{10}{9}:\frac{5}{4}=\frac{10}{9}.\frac{4}{5}=\frac{8}{9}\)
( 2015 - x ) : 29 + 32 = 100
( 2015 - x ) : 29 = 100 - 32
( 2015 - x ) : 29 = 68
2015 - x = 68 x 29
2015 - x = 1972
x = 2015 - 1972
x = 43
L i k e nha các bạn !!!
(2015-x):26=100-32
(2015-x):26=68
2015-x=68x26
2015-x=1768
x=2015-1768
x=247