Question

[Hương Giang]

tìm x:

a) \(2^{3+2x}\) + \(2^{2x+1}\) + \(2^x=176\)

B) \(2^{2x+3}+2^{1+2x}-2^{2x}=144\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\Leftrightarrow2^{2x}\cdot8+2^{2x}\cdot2+2^{2x}=176\)

\(\Leftrightarrow2^{2x}=16\)

=>2x=4

=>x=2

b: \(\Leftrightarrow2^{2x}\left(2^3+2-1\right)=144\)

\(\Leftrightarrow2^{2x}=16\)

=>2x=4

=>x=2