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Bài 1:
Ta có: \(4-2\left(x+1\right)=2\)
\(\Leftrightarrow2\left(x+1\right)=2\)
\(\Leftrightarrow x+1=1\)
hay x=0
Bài 2:
Ta có: \(\left|2x-3\right|-1=2\)
\(\Leftrightarrow\left|2x-3\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
a: =>(2x+1/2)^2=1/4
=>2x+1/2=1/2 hoặc 2x+1/2=-1/2
=>x=-1/2 hoặc x=0
b: =>(x-1/5)^2=49
=>x-1/5=7 hoặc x-1/5=-7
=>x=-6,8 hoặc x=7,2
c: =>1,2x=12
=>x=10
d: =>3/4x+1/2x+1/2=-11/4
=>5/4x=-11/4-2/4=-13/4
=>x=-13/5
e: =>-0,25x+1,25x=0,2
=>x=0,2
`@` ` \text {Ans}`
`\downarrow`
`a,`
`1/4+3/4*x=3/2-x`
`=> 1/4 + 3/4x - 3/2 + x = 0`
`=> (1/4 - 3/2) + (3/4x + x) = 0`
`=> -5/4 + 7/4x = 0`
`=> 7/4x = 5/4`
`=> x = 5/4 \div 7/4`
`=> x = 5/7`
Vậy, `x=5/7`
`b,`
`3/5*x-1/4=1/10*x-1/2`
`=> 3/5x - 1/4 - 1/10x + 1/2 = 0`
`=> (3/5x - 1/10x) + (-1/4 + 1/2)=0`
`=> 1/2x + 1/4 = 0`
`=> 1/2x = -1/4`
`=> x = -1/4 \div 1/2`
`=> x = -1/2`
Vậy, `x=-1/2`
`c,`
`3x-3/5=x-1/4`
`=> 3x - 3/5 - x + 1/4 = 0`
`=> (3x - x) - (3/5 - 1/4) = 0`
`=> 2x - 7/20 = 0`
`=> 2x = 0,35`
`=> x = 0,35 \div 2`
`=> x = 7/40`
Vậy, `x=7/40`
`d,`
`3/2*x-2/5=1/3*x-1/4`
`=> 3/2x - 2/5 - 1/3x + 1/4 = 0`
`=> (3/2x - 1/3x) - (2/5 - 1/4) = 0`
`=> 7/6x - 3/20 = 0`
`=> 7/6x = 3/20`
`=> x = 3/20 \div 7/6`
`=> x = 9/70`
Vậy, `x=9/70`
`@` `\text {Kaizuu lv uuu}`
\(a,x+\dfrac{1}{4}\times\dfrac{1}{5}=\dfrac{4}{5}\)
\(x+\dfrac{1}{20}=\dfrac{4}{5}\)
\(x=\dfrac{4}{5}-\dfrac{1}{20}\)
\(x=\dfrac{16}{20}-\dfrac{1}{20}\)
\(x=\dfrac{15}{20}=\dfrac{3}{4}\)
\(b,3\dfrac{2}{3}:x=2\dfrac{2}{3}-1\dfrac{1}{2}\)
\(\dfrac{11}{3}:x=\dfrac{8}{3}-\dfrac{3}{2}\)
\(\dfrac{11}{3}:x=\dfrac{7}{6}\)
\(x=\dfrac{11}{3}:\dfrac{7}{6}=\dfrac{22}{7}\)
a: =>x+1/20=4/5
=>x=4/5-1/20=16/20-1/20=15/20=3/4
b: =>11/3:x=8/3-3/2=16/6-9/6=7/6
=>x=11/3:7/6=11/3*6/7=66/21=22/7
a)
`x+1/4xx1/5=4/5`
`x+1/20=4/5`
`x=4/5-1/20`
`x=16/20-1/20`
`x=15/20=3/4`
b)
`3 2/3:x=2 2/3-1 1/2`
`11/3:x=8/3-3/2`
`11/3:x=16/6-9/6`
`11/3:x=7/6`
`x=11/3:7/6`
`x=11/3xx6/7`
`x=22/7`
\(a,x+\dfrac{1}{4}.\dfrac{1}{5}=\dfrac{4}{5}\)
\(\Rightarrow\)\(x+\dfrac{1}{20}=\dfrac{4}{5}\)
\(\Rightarrow x=\dfrac{4}{5}-\dfrac{1}{20}=\dfrac{16}{20}-\dfrac{1}{20}=\dfrac{3}{4}\)
\(b,3\dfrac{2}{3}:x=2\dfrac{2}{3}-1\dfrac{1}{2}\)
\(\Rightarrow\dfrac{11}{3}:x=\dfrac{7}{6}\)
\(\Rightarrow x=\dfrac{11}{3}:\dfrac{7}{6}=\dfrac{22}{7}\)
\(x-\dfrac{1}{2}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}+\dfrac{1}{2}\)
\(x=\dfrac{5}{4}\)
\(x+\dfrac{7}{8}=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}-\dfrac{7}{8}\)
\(x=\dfrac{-1}{8}\)
\(\dfrac{1}{2}\cdot x-\dfrac{1}{4}=\dfrac{-1}{2}\)
\(\dfrac{1}{2}\cdot x=\dfrac{-1}{2}+\dfrac{1}{4}\)
\(\dfrac{1}{2}\cdot x=\dfrac{-1}{4}\)
\(x=\dfrac{-1}{4}\div\dfrac{1}{2}\)
\(x=\dfrac{-1}{2}\)
Câu D ko bt
a: x*3/4=1/5
=>x=1/5:3/4=1/5*4/3=4/15
b: x*3/7=2/5
=>x=2/5:3/7=2/5*7/3=14/15
c: 1/3+2/9=2/12x
=>1/6x=3/9+2/9=5/9
=>x=5/9*6=30/9=10/3
d: 4/15*x-2/3=1/5
=>4/15*x=2/3+1/5=10/15+3/15=13/15
=>4x=13
=>x=13/4
e: x:1/7=2/3
=>x=2/3*1/7=2/21
f: 1/9:x=7/3
=>x=1/9:7/3=1/9*3/7=3/63=1/21
j: 1/4+5/12=8/3:x
=>8/3:x=3/12+5/12=8/12=2/3
=>x=4
h: =>7/4:x=1/5+1/2=7/10
=>x=7/4:7/10=10/4=5/2
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\(4-x:\frac{1}{2}=\frac{1}{2}\)
\(x:\frac{1}{2}=4-\frac{1}{2}\)
\(x:\frac{1}{2}=\frac{7}{2}\)
\(x=\frac{7}{2}\times\frac{1}{2}\)
\(x=\frac{7}{4}\)
Học tốt
\(4-x:\frac{1}{2}=\frac{1}{2}\)
\(x:\frac{1}{2}=4-\frac{1}{2}=\frac{8}{2}-\frac{1}{2}\)
\(x:\frac{1}{2}=\frac{7}{2}\)
\(x=\frac{7}{2}.\frac{1}{2}\)
\(x=\frac{7}{4}=1\frac{3}{4}\)