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\(4x+\frac{1}{2}=5x-\frac{3}{4}\)
\(\Rightarrow4x-5x=-\frac{3}{4}-\frac{1}{2}\)
\(\Rightarrow-1x=-\frac{5}{2}\)
\(\Rightarrow x=\frac{5}{2}\)
Lời giải:
1. $(x+2)-2=0$
$x+2=2$
$x=0$
2.
$(x+3)+1=7$
$x+3=7-1=6$
$x=6-3=3$
3.
$(3x-4)+4=12$
$3x-4+4=12$
$3x=12$
$x=12:3=4$
4.
$(5x+4)-1=13$
$5x+4=13+1=14$
$5x=14-4=10$
$x=10:5=2$
5.
$(4x-8)-3=5$
$4x-8=5+3=8$
$4x=8+8=16$
$x=16:4=4$
6.
$3+(x-5)=7$
$x-5=7-3=4$
$x=4+5=9$
7.
$8-(2x-4)=2$
$2x-4=8-2=6$
$2x=6+4=10$
$x=10:2=5$
8.
$7+(5x+2)=14$
$5x+2=14-7=7$
$5x=7-2=5$
$x=5:5=1$
9.
$5-(3x-11)=1$
$3x-11=5-1=4$
$3x=11+4=15$
$x=15:3=5$
10.
$16-(8x+2)=6$
$8x+2=16-6=10$
$8x=10-2=8$
$x=8:8=1$
a) 3x2 + 12x =0
<=> 3x( x+ 4)=0
<=> \(\orbr{\begin{cases}3x=0\\x+4=0\end{cases}}\) <=>\(\orbr{\begin{cases}x=0\\x=-4\end{cases}}\)
d) \(4x^3=4x\)
<=> \(4x^3-4x=0\)
<=> 4x( x2 -1) =0
<=> 4x ( x - 1) ( x+ 1) =0
<=> 4x=0 hoac x-1=0 hoac x+1=0
<=> x=0 hoac x=1 hoac x=-1
\(\frac{3}{4}x-\frac{5}{7}=\frac{3}{5}x+\frac{1}{2}\)
\(\Leftrightarrow\frac{3}{4}x-\frac{3}{5}x=\frac{1}{2}+\frac{5}{7}\)
\(\Leftrightarrow x.\left(\frac{3}{4}-\frac{3}{5}\right)=\frac{17}{14}\)
\(\Leftrightarrow x.\frac{3}{20}=\frac{17}{14}\)
\(\Leftrightarrow x=\frac{170}{21}\)
a: =>x:2,2=15,2x2=30,4
=>x=66,88
b: =>(15/4x+3/4)=-2/3
=>15/4x=-17/12
hay x=-17/45
2/5x=1-3/4=1/4=1/4:25=5\8
\(\dfrac{3}{4}x+\dfrac{2}{5}x=1\)
\(=>x\left(\dfrac{3}{4}+\dfrac{2}{5}\right)=1\)
\(=>x\left(\dfrac{15}{20}+\dfrac{8}{20}\right)=1\)
\(=>\dfrac{23}{20}x=1\)
\(=>x=\dfrac{20}{23}\)