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(1/11-1/13+1/13-1/15+.....+1/19-1/21)*462-y=19
(1/11-1/21)*462-y=19
10/231*462-y=19
20-y=19
y=1
Nhân thêm 2
=>(13-11/11x13+...+21-19/19x21)-x+221/231=4/3
=>(13/11x13-11/11x13+...+21/19x21-19/19x21)-x+221/231=4/3
=>(1/11-1/13+...+1/18-1/21)-x+221/231=4/3
=>(1/11-1/21)-x+221/231=4/3
=>10/231-x+221/231=4/3
=>10/231+221/231-x=4/3
=>231/231-x=4/3
=>1-x=4/3
=>x=1-4/3=-1/3
\(\left(\frac{2}{11x13}+\frac{2}{13x15}+\frac{2}{15x17}+\frac{2}{17x19}+\frac{2}{19x21}\right)\)) x 462 - y = 19
\(=\left(\frac{13-11}{11x13}+\frac{15-13}{13x15}+\frac{17-15}{15x17}+\frac{19-17}{17x19}+\frac{21-19}{19x21}\right)\)x 462 - y = 19
\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\)) x 462 - y = 19
\(=\left(\frac{1}{11}-\frac{1}{21}\right)\)x 462 - y = 19
\(=\left(\frac{21}{231}-\frac{11}{231}\right)\)x 462 - y = 19
\(=\frac{10}{231}\)x 462 - y = 19
\(=20\)- y = 19
y = 20 - 19
y = 1
\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
Ta có:
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+....+\frac{1}{19}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\frac{10}{231}-x+\frac{221}{231}=\frac{4}{3}\)
\(\frac{10}{231}-x=\frac{4}{3}-\frac{221}{231}=\frac{29}{77}\)
\(x=\frac{10}{231}-\frac{29}{77}\)
\(x=-\frac{1}{3}\)
(11×132+13×152+15×172+17×192+19×212)×462−y=19
⇒(111−113+113−115+115−117+117−119+119−121)×462−�=19⇒(111−131+131−151+151−171+171−191+191−211)×462−y=19
⇒(111−121)×462−�=19⇒10231×462−�=19⇒(111−211)×462−y=19⇒23110×462−y=19
⇒20−�=19⇒�=20−19=1⇒20−y=19⇒y=20−19=1
Tìm \(x\) biết:
(\(\dfrac{2}{11\times13}\) + \(\dfrac{2}{13\times15}\)+...+ \(\dfrac{2}{19\times21}\)) x 462 - (204: (\(x-105\)):12) =19
(\(\dfrac{1}{11}-\dfrac{1}{13}\)+ \(\dfrac{1}{13}\) - \(\dfrac{1}{15}\)+...+ \(\dfrac{1}{19}\) - \(\dfrac{1}{21}\)) x 462 - (204 : (\(x\) -105):12) =19
(\(\dfrac{1}{11}\) - \(\dfrac{1}{21}\)) x 462 - \(\dfrac{204:(x-105)}{12}\) = 19
\(\dfrac{10}{213}\) x 462 - \(\dfrac{204:\left(x-105\right)}{12}\) = 19
20 - \(\dfrac{204:\left(x-105\right)}{12}\) = 19
204:(\(x\) - 105):12 = 20 - 19
204:(\(x-105\)):12 = 1
204: (\(x\) - 105) = 12
\(x-105\) = 204: 12
\(x\) - 105 = 17
\(x\) = 17 + 105
\(x\) = 122