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n: (-8)*x+17=-23
=>\(x\cdot\left(-8\right)=-23-17=-40\)
=>\(x\cdot8=40\)
=>\(x=\dfrac{40}{8}=5\)
o: \(\left(-15\right)\cdot x=10\left(-4\right)-5\)
=>\(x\cdot\left(-15\right)=-40-5=-45\)
=>\(x\cdot15=45\)
=>\(x=\dfrac{45}{15}=3\)
p: \(\left(-3\right)\cdot x-4=2\cdot\left(-7\right)+4\)
=>\(\left(-3\right)\cdot x-4=-14+4=-10\)
=>\(x\left(-3\right)=-10+4=-6\)
=>\(3x=6\)
=>\(x=\dfrac{6}{3}=2\)
q: x+x+x+91=-2
=>\(3x+91=-2\)
=>\(3x=-2-91=-93\)
=>\(x=-\dfrac{93}{3}=-31\)
r: \(-152-\left(3x+1\right)=\left(-2\right)\cdot\left(-27\right)\)
=>\(-152-3x-1=54\)
=>\(-153-3x=54\)
=>\(3x=-153-54=-207\)
=>\(x=-\dfrac{207}{3}=-69\)
Bài 1 . Tìm x
a) 723 - ( 7x - 152 ) = 714
7x - 152 = 723 - 714
7x - 152 = 9
7x = 9 + 152
7x = 161
x = 161 : 7
x = 23
Vậy x = 23
b) ( 2x - 130 ) : 4 + 213 = 52 + 193
( 2x - 130 ) : 4 + 213 = 218
( 2x - 130 ) : 4 = 218 - 213
( 2x - 130 ) : 4 = 5
2x - 130 = 5 . 4
2x - 130 = 20
2x = 20 + 130
2x = 150
x = 150 : 2
x = 75
Vậy x = 75
c) ( x - 6 )2 = 9
( x - 6 )2 = 32
x - 6 = 3 <=> x = 3 + 6 <=> x = 9
x - 6 = -3 <=> x = -3 + 6 <=> x = 3
a) 5(-x - 2) = 0
-x - 2 = 0
-x = 0 + 2
-x = 2
x = -2 (nhận)
Vậy x = -2
b) (-4).x = 26
x = 26 : (-4)
x = -13/2 (loại)
Vậy không tìm được x là số nguyên thỏa mãn đề bài
c) -152 - (3x + 1) = (-2).27
-152 - (3x + 1) = -54
3x + 1 = -152 + 54
3x + 1 = -98
3x = -98 - 1
3x = -99
x = -99 : 3
x = -33 (nhận)
Vậy x = -33
\(8x-48+4x-12-14=-x+4\)
\(\Leftrightarrow12x-75=-x+4\Leftrightarrow13x=79\Leftrightarrow x=\dfrac{79}{13}\)
\(-7\left(8-x\right)-6\left(x+9\right)=20-x\Leftrightarrow-56+7x-6x-54=20-x\)
\(\Leftrightarrow2x=130\Leftrightarrow x=65\)
\(9x-63-80+60x=-7x+15\Leftrightarrow76x=158\Leftrightarrow x=\dfrac{79}{38}\)
\(-96-16x-60+30x=-40x-16\Leftrightarrow54x=140\Leftrightarrow x=\dfrac{70}{27}\)
\(17x-102-14x-28=4x-24-2x+4\Leftrightarrow x=110\)
1) |x + 2| = 4
\(\Leftrightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=-6\end{cases}}\)
2) 3 – |2x + 1| = (-5)
\(\Leftrightarrow\left|2x+1\right|=8\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}\)
3) 12 + |3 – x| = 9
\(\Leftrightarrow\left|3-x\right|=-3\)(vô lí)
=>\(x=\varnothing\)
1) I x+2 I=4
\(\Rightarrow\orbr{\begin{cases}x+2=4\\x+2=-4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-6\end{cases}}}\)
2) \(3-|2x+1|=-5\)
\(\Leftrightarrow|2x+1|=8\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-9\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-9}{2}\end{cases}}}\)
3) \(12+|3-x|=9\)
\(\Leftrightarrow|3-x|=-3\)(vô lí vì I 3-x I \(\ge\)0)
\(152:\left(4x+6:2\right)\times9=\left(-4\right)\times\left(-2\right)\\ =>152:\left(4x+3\right)\times9=8\\ =>152:\left(4x+3\right)=\dfrac{8}{9}\\ =>4x+3=152:\dfrac{8}{9}\\ =>4x+3=152\times\dfrac{9}{8}\\ =>4x+3=171\\ =>4x=171-3\\ =>4x=168\\ =>x=168:4\\ =>x=42\)
152 : (4x +3) x 9 = 8
(4x + 3) x 9 = 19
4x + 3 = \(\dfrac{19}{9}\)
4x = \(\dfrac{-8}{9}\)
x = \(\dfrac{-2}{9}\)