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135 - (2 - x) = ( x - 934) - 16
=> 135 - 2 + x = x - 934 - 16
=> 133 + x = x - 920
=> 133 + 920 = 2x
=> 1053 = 2x
=> x = 1053 / 2
135-(2-x)=(x-934)-16
(x-934)-(2-x)=135-16=119
2x-934-2=119
2x-932=119
2x=119+932
2x=1051
x=1051:2
x=525,5
135 + ( 121 - x ) = 231
121 - x = 231 - 135
121 - x = 96
x = 121 - 96
x = 25
x - 32 : 16 = 48
x- 2 = 48
x= 48 + 2
x = 50
\(\text{ x-1=-10-3}\)
\(x-1=-13\)
\(x=-12\)
\(\text{|x+2|=12+(-3)+|-4|}\)
\(\text{|x+2|}=12-3+4\)
\(\text{|x+2|}=13\)
\(\Rightarrow\orbr{\begin{cases}x+2=13\\x+2=-13\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-15\end{cases}}}\)
\(\text{|x+2|-12=-1}\)
\(\text{|x+2|}=11\)
\(\Rightarrow\orbr{\begin{cases}x+2=11\\x+2=-11\end{cases}\Leftrightarrow\orbr{\begin{cases}x=9\\x=-13\end{cases}}}\)
\(\text{|2x+3|=5}\)
\(\Rightarrow\orbr{\begin{cases}2x+3=5\\2x+3=-5\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=2\\2x=-8\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=-4\end{cases}}}\)
\(\text{135-|9-x|=35}\)
\(\text{|9-x|}=100\)
\(\Rightarrow\orbr{\begin{cases}9-x=100\\9-x=-100\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-191\\x=109\end{cases}}}\)
chúc bạn học tốt
a) x + 10 = 20
<=> x = 20 - 10 = 10
Vậy x = 10
b) 2x + 15 = 35
<=> 2x = 35 - 15 = 20
<=> x = 10
Vậy x = 10
c) 3(x + 2) = 15
<=> x + 2 = 15 : 3 = 5
<=> x = 5 - 2 = 3
Vậy x = 3
d) 10x + 15.11 = 20.10
<=> 10x + 165 = 200
<=> 10x = 200 - 165 = 35
<=> x = 35 : 10 = 3,5
Vậy x = 3,5
e) 4(x + 2) = 3.4
<=> x + 2 = 3
<=> x = 3 - 2 = 1
Vậy x = 1
f) 33x + 135 = 26.9
<=> 33x + 135 = 234
<=> 33x = 234 - 135 = 99
<=> x = 99 : 33 = 3
Vậy x = 3
g) 2x + 15 + 16 + 17 = 100
<=> 2x + 48 = 100
<=> 2x = 100 - 48 = 52
<=> x = 52 : 2 = 26
Vậy x = 26
h) 2(x + 9 + 10 + 11) = 4.12.5
<=> x + 30 = 120
<=> x = 120 - 30 = 90
Vậy x = 90
\(\frac{1}{8}\cdot16^x=2^x\)
\(\Leftrightarrow\frac{1}{8}=\frac{2^x}{16^x}\)
\(\Leftrightarrow\left(\frac{2}{16}\right)^x=\frac{1}{8}\)
\(\Leftrightarrow\left(\frac{1}{8}\right)^x=\frac{1}{8}\)
Suy ra x=1
`@` `\text {Ans}`
`\downarrow`
`a)`
`x + 10 = 20`
`=> x = 20 -10`
`=> x = 10`
Vậy, `x = 10`
`b)`
`2 * x + 15 = 35`
`=> 2x = 35 - 15`
`=> 2x = 20`
`=> x = 20 \div 2`
`=> x = 10`
Vậy, `x = 10`
`c)`
`3 * ( x + 2 ) = 15`
`=> x + 2 = 15 \div 3`
`=> x + 2 = 5`
`=> x = 5 - 2`
`=> x = 3`
Vậy, `x = 3`
`d)`
`10 * x + 15 * 11 = 20 * 10`
`=> 10x + 165 = 200`
`=> 10x = 200 - 165`
`=> 10x = 35`
`=> x = 35 \div 10`
`=> x = 3,5`
Vậy,` x = 3,5`
`e)`
`4 * ( x + 2 ) = 3 * 4`
`=> x + 2 = 12 \div 4`
`=> x + 2 = 3`
`=> x = 3 - 2`
`=> x = 1`
Vậy,` x = 1`
`f)`
`33 x + 135 = 26 * 9`
`=> 33x + 135 = 234`
`=> 33x = 234 - 135`
`=> 33x = 99`
`=> x = 99 \div 33`
`=> x = 3`
Vậy, `x = 3`
`g)`
`2 * x + 15 + 16 + 17 = 100`
`=> 2x + 48 = 100`
`=> 2x = 100 - 48`
`=> 2x = 52`
`=> x = 52 \div 2`
`=> x =26`
`h)`
`2 * (x + 9 + 10 + 11) = 4 . 12 . 25`
`=> 2 * (x + 9 + 10 + 11) = 4*25*12`
`=> 2 * (x + 9 + 10 + 11) = 100*12`
`=> x + 9 + 10 + 11 = 100*12 \div 2`
`=> x + 30 = 600`
`=> x = 600 - 30`
`=> x = 570`
Vậy, `x = 570.`
a) \(x+10=20\Leftrightarrow x=10\)
b) \(2x+15=35\Leftrightarrow2x=20\Leftrightarrow x=10\)
c) \(3.\left(x+2\right)=15\Leftrightarrow x+2=5\Leftrightarrow x=3\)
d) \(10x+15.11=20.10\Leftrightarrow10x+165=200\Leftrightarrow10x=35\Leftrightarrow x=\dfrac{35}{10}=\dfrac{7}{2}\)
e) \(4.\left(x+2\right)=3.4\Leftrightarrow x+2=3\Leftrightarrow x=1\)
f) \(35x+135=26.9\Leftrightarrow35x=234-135\Leftrightarrow35x=99\Leftrightarrow x=\dfrac{99}{35}\)
g) \(2x+15+16+17=100\Leftrightarrow2x+48=100\Leftrightarrow2x=52\Leftrightarrow x=26\)
h) \(2.\left(x+9+10+11\right)=4.12.25\)
\(\Leftrightarrow x+30=2.12.25\)
\(\Leftrightarrow x=600-30\)
\(\Leftrightarrow x=570\)
135 - ( 2 - x ) = ( x - 934 ) - 16
\(\Leftrightarrow\) 135 - 2 + x = x - 934 - 16
\(\Leftrightarrow\) 135 - 2 + x = x - 950
\(\Leftrightarrow\) 0x = 950 - 135 + 2
\(\Leftrightarrow\) 0x = 717
\(\Leftrightarrow\) x \(\in\varnothing\)