Question

[Đan Nguyễn]

tìm nghiệm ạaa

Answer 1

[YangSu]

Đặt \(M\left(x\right)=0\Rightarrow3.\left(2-x\right)+\left(x-2\right)^2=0\)

\(\Rightarrow-3.\left(x-2\right)+\left(x-2\right)^2=0\)

\(\Rightarrow\left(x-2\right).\left[\left(-3\right)+\left(x-2\right)\right]=0\\ \Rightarrow\left(x-2\right).\left(x-2-3\right)=0\\ \Rightarrow\left(x-2\right).\left(x-5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x-5=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

Vậy \(M\left(x\right)\) có nghiệm là \(x=2,x=5\).

Answer 2

[⭐Hannie⭐]

`M(x)=3.(2-x)+(x-2)^2`

Ta có :

`3.(2-x)+(x-2)^2=0`

`=>3.(2-x)+(2-x)^2=0`

`=>(2-x).(3+2-x)=0`

`=>(2-x).(5-x)=0`

\(\Rightarrow\left[{}\begin{matrix}2-x=0\\5-x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)