Question

[Nguyễn Thùy Linh]

tìm ĐKXĐ

1, \(\sqrt{6x+1}\)

2,\(\dfrac{\sqrt{3}-4}{\sqrt{3x-5}}\)

3, \(\sqrt{\dfrac{2\sqrt{15}-\sqrt{59}}{x-7}}\)

4,\(\sqrt{\dfrac{-3x}{1-\sqrt{2}}}\)

5, \(\sqrt{\sqrt{5}-\sqrt{3}x}\)

Answer 1

[Dang Tung]

1.

6x + 1 ≥0

<=>6x≥-1

<=>x≥-1/6

2.

3x - 5 > 0 

<=> 3x > 5

<=> x > 5/3

Answer 2

[Dang Tung]

3.

x - 7 > 0

<=> x > 7

4. 

-3x ≥0

<=>x≤0