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a, Ta có: 10 = 2.5; 12 = 2 2 .3
BCNN(10,12) = 2 2 .3.5 = 60
b, Ta có: 24 = 2 3 .3; 56 = 2 3 .7
BCNN(24;56) = 2 3 .3.7 = 168
c, Ta có: 84 = 2 2 .3.7; 108 = 2 2 . 3 3
BCNN(84;108) = 2 2 . 3 3 .7
d, Ta có: 33 = 3.11; 44 = 4.11; 55 = 5.11
BCNN(33;44;55) = 3.4.5.11 = 660
e, Ta có: 8 = 2 3 ; 18 = 2. 3 2 ; 30 = 2.3.5
BCNN(8,18,30) = 2 3 . 3 2 . 5 = 360
f, Ta có: 40 = 2 3 . 5 ; 28 = 2 2 .7; 140 = 2 2 .5.7
BCNN(40;28;140) = 2 3 . 5 . 7 = 280
BCNN(15;3) = 15
BCNN(11;3;33) = 33
BCNN(6;2;12) = 36
BCNN(4;3;15) = 60
a, 15 = 3 . 5
45 = 32 . 5
=> UCLN = 3 . 5 = 15
BCNN = 32 . 5 = 45
b, 7 = 1 . 7
9 = 32
12 = 22 . 3
=> UCLN = 1
BCNN = 32 . 22 . 7 = 252
c, 12 = 22 . 3
14 = 2. 7
18 = 2 . 32
UCLN = 2
BCNN = 22 . 32 . 7 = 252
d , 11 = 11 . 1
33 = 3 . 11
99 = 32 . 11
=> UCLN = 11
BCNN = 32 . 11 = 99
a: \(42=2\cdot3\cdot7;70=2\cdot5\cdot7\)
=>\(BCNN\left(42;70\right)=2\cdot3\cdot5\cdot7=210\)
=>\(BC\left(42;70\right)=B\left(210\right)=\left\{0;210;420;...\right\}\)
b: \(70=2\cdot5\cdot7;180=3^2\cdot5\cdot2^2\)
=>\(BCNN\left(70;180\right)=2^2\cdot3^2\cdot5\cdot7=1260\)
=>\(BC\left(70;180\right)=\left\{1260;2520;...\right\}\)
c: \(5=5;7=7;8=2^3\)
=>\(BCNN\left(5;7;8\right)=5\cdot7\cdot8=280\)
=>\(BC\left(5;7;8\right)=\left\{280;560;...\right\}\)
d: \(12=2^2\cdot3;18=3^2\cdot2\)
=>\(BCNN\left(12;18\right)=2^2\cdot3^2=36\)
=>\(BC\left(12;18\right)=\left\{36;72;...\right\}\)
e: \(15=3\cdot5;18=3^2\cdot2\)
=>\(BCNN\left(15;18\right)=3^2\cdot2\cdot5=90\)
=>\(BC\left(15;18\right)=\left\{90;180;...\right\}\)
f: \(84=2^2\cdot3\cdot7;108=3^3\cdot2^2\)
=>\(BCNN\left(84;108\right)=2^2\cdot3^3\cdot7=756\)
=>\(BC\left(84;108\right)=\left\{756;1512;...\right\}\)
j: \(33=3\cdot11;44=2^2\cdot11;55=5\cdot11\)
=>\(BCNN\left(33;44;55\right)=3\cdot2^2\cdot5\cdot11=660\)
=>\(BC\left(33;44;55\right)=\left\{660;1320;...\right\}\)
g: \(1=1;12=2^2\cdot3;27=3^3\)
=>\(BCNN\left(1;12;27\right)=1\cdot2^2\cdot3^3=108\)
=>\(BC\left(1;12;27\right)=\left\{108;216;...\right\}\)
n: \(5=5;9=3^2;11=11\)
=>\(BCNN\left(5;9;11\right)=5\cdot3^2\cdot11=495\)
=>\(BC\left(5;9;11\right)=\left\{495;990;...\right\}\)
phân tích các số ra thừa số nguyên tố :
12=2^2.3
18=2.3^2
do đó : BCNN(12;18)= 2^2.3^2=36
vậy: BCNN(12;18)=36