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A:
\(Cu\left(OH\right)_2--to->CuO+H_2O\)
\(CuO+2HCl-->CuCl_2+H_2O\)
\(CuCl_2+2NaOH-->Cu\left(OH\right)_2+2NaCl\)
\(Cu\left(OH\right)_2+H_2SO_4-->CuSO_4+2H_2O\)
B:
\(Mg\left(OH\right)_2--to->MgO+H_2O\)
\(MgO+2HCl-->MgCl_2+H_2O\)
\(MgCl_2+2NaOH-->Mg\left(OH\right)_2+2NaCl\)
\(Mg\left(OH\right)_2+H_2SO_4-->MgSO_4+2H_2O\)
A: Cu(OH)2 \(\underrightarrow{t^o}\) CuO + H2O
CuO + 2HCl \(\rightarrow\) CuCl2 + H2O
CuCl2 +2 NaOH \(\rightarrow\) Cu(OH)2 + NaCl
Cu(OH)2 + H2SO4 \(\rightarrow\) CuSO4 + 2H2O
B: Mg(OH)2 \(\underrightarrow{t^o}\) 2MgO + H2O
MgO + 2HCl \(\rightarrow\) MgCl2 + H2O
MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + NaCl
Mg(OH)2 + H2SO4 \(\rightarrow\) MgSO4 + 2H2O
Giải được câu A rồi thì câu B làm tương tự thôi
2Mg+O2--> 2MgO(1)
MgO+2HCl-->MgCl2+H2O(2)
MgCl2+2NaOH--> Mg(OH)2+2NaCl(3)
Mg(OH)2+CuSO4-->MgSO4+Cu(OH)2(4)
MgSO4+Ba(NO3)2-->Mg(NO3)2+BaSO4(5)
CuO+H2SO4-->CuSO4+H2O(1)
CuSO4+2NaOH-->Cu(OH)2+Na2SO4(2)
Cu(OH)2+2HCl-->CuCl2+2H2O(3)
CuCl2+2AgNO3-->Cu(NO3)2+2AgCl(4)
Cu(NO3)2+Mg-->Mg(NO3)2+Cu(5)
1)\(Mg\left(OH\right)_2\underrightarrow{t^o}MgO+H_2O\)
2)\(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)
3)\(MgSO_4+BaCl_2\rightarrow MgCl_2+BaSO_4\downarrow\)
4)\(MgCl_2+2AgNO_3\rightarrow Mg\left(NO_3\right)_2+2AgCl\downarrow\)
5)\(MgSO_4+Ba\left(OH\right)_2\rightarrow BaSO_4\downarrow+Mg\left(OH\right)_2\downarrow\)
a.
2Al2O3 \(\underrightarrow{t^o}\)4Al + 3O2\(\uparrow\)
Al + 6HNO3 \(\rightarrow\) Al(NO3)3\(\downarrow\) + 3NO2 + 3H2O
Al(NO3)3 + NaOH \(\rightarrow\) Al(OH)3\(\downarrow\) + NaNO3
2Al(OH)3 \(\xrightarrow[criolit]{đpnc}\) Al2O3 + 3H2O
Al2O3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 3H2O
Al2(SO4)3 + 3BaCl2 \(\rightarrow\) 3BaSO4\(\downarrow\) + 2AlCl3
2AlCl3 \(\xrightarrow[criolit]{đpnc}\) 2Al + 3Cl2\(\uparrow\)
2Al + 3CuSO4 \(\rightarrow\) 3Cu + Al2(SO4)3
A: Cu(OH)2 \(\underrightarrow{t^o}\) CuO + H2O
CuO + 2HCl → CuCl2 + H2O
CuCl2 +2 NaOH → Cu(OH)2 + NaCl
Cu(OH)2 + H2SO4 → CuSO4 + 2H2O
B: Mg(OH)2 \(\underrightarrow{t^o}\) 2MgO + H2O
MgO + 2HCl → MgCl2 + H2O
MgCl2 + 2NaOH → Mg(OH)2 + NaCl
Mg(OH)2 + H2SO4 → MgSO4 + 2H2O