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d) Ta có: \(-8+\left(-14\right)+34+\left(-12\right)\)
\(=-8-14+34-12\)
\(=-20+20\)
\(=-0\)
e) Ta có: \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=\left(-7+57\right)+\left(-20-30\right)\)
\(=50-50=0\)
f) Ta có: \(300-\left(-180\right)-120-42\)
\(=300+180-120-42\)
\(=258+60=318\)
d, Ta có : \(\left(-8\right)+\left(-14\right)+34+\left(-12\right)\)
\(=-\left(8+12\right)+34-14=-20+20=0\)
e, Ta có : \(\left(-7\right)+\left(-20\right)+57+\left(-30\right)\)
\(=-\left(30+20\right)+57-7=-50+50=0\)
f, Ta có : \(300-\left(-180\right)-120-42=318\)
− 5 7 + 14 11 − 11 14 − 14 − 11 = − 5 7 − 11 14 = − 21 14 = − 3 2 .
A) 195 x 63 + 37 x195
195 x ( 63 + 37 ) = 195 x 100
= 19500
B) 7^12 : 7^10 - 36 : 3^2
= 7^12-10 - 36 : 9
= 7^2 - 4 = 49 - 4 = 45
C) 180 - [130-(12-10)^3] + 2023^0
= 180 -(130-2^3)+1
= 180-130+8+1
= 50 + 8+1 = 59
\(a,195.63+37.195\)
\(=195\left(63+37\right)\)
\(=195.100\)
\(=19500\)
\(b,7^{12}:7^{10}-36:3^2\)
\(=7^2-2^2.3^2:3^2\)
\(=7^2-2^2\)
\(=49-4=44\)
\(c,180-\left[130-\left(12-10\right)^3\right]+2023^0\)
\(=180-\left[130-2^3\right]+1\)
\(=180-\left(130-8\right)+1\)
\(=180-122+1\)
\(=59\)
Có gì k hiểu thì ib nhá
a) \(35\left(14-101\right)-14\left(35-10\right)\)
\(=35\cdot14-35\cdot101-14\cdot35+14\cdot10\)
\(=140-3535=-3395\)
b) \(5^2\cdot\left(-3\right)^3=25\cdot\left(-27\right)=-675\)
a: 86+357+14
=100+357
=457
b: \(3\cdot52-16:22\)
\(=156-\dfrac{8}{11}=\dfrac{1708}{11}\)
a) \(17+188+183=205+183=388\)
b) \(80-\left[130-\left(12-4\right)^2\right]\)
\(=80-\left(130-64\right)\)
\(80-66=14\)
c) \(2^3.17-2^3.14\)
\(8.17-8.14\)
\(=8.\left(17-14\right)\)
\(=8.3=24\)
a)5*2^2-18:3=20-6=14
b)17*85+15*17-120=17*(120-85+15)=17*20=340
c2^3*17-2^3*14=2^3(17-14)=8*3=24
25 . 17 . 4 = 425 . 4 = 1700
35 . 81 + 35 . 19 = 35.(81+19) =35 . 100 =3500
180-[110-(14-5)\(^2\)] =180-[110-9\(^2\)] =180-[110-81] =180-29=151
Chúc bạn học tốt !
25 × 17 ×4 =25 × 4 × 17 =100 ×17 = 1700
35 ×81 +35 ×19 = 35 × ( 81 + 19 ) = 35 × 100 = 3500
180 -[ 110 - ( 14 -5 )2 ]
180 -(110 - 92)
180 -( 110 -81 )
180 - 29
151