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a) \(27\cdot75+25\cdot27-150\cdot2023^0\)
\(=27\cdot\left(75+25\right)-150\cdot1\)
\(=27\cdot100-150\)
\(=2700-150\)
\(=2550\)
b) \(3^x+3^{x+1}+16\cdot4=2^2\cdot5^2\)
\(\Rightarrow3^x+3^x\cdot3=100-64\)
\(\Rightarrow3^x\cdot\left(1+3\right)=36\)
\(\Rightarrow3^x\cdot4=36\)
\(\Rightarrow3^x=36:4\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 27.75 + 25.27 - 150.2023⁰
= 27.(75 + 25) - 150.1
= 27.100 - 150
= 2700 - 150
= 2550
b) 3ˣ + 3ˣ⁺¹ + 16.4 = 2².5²
3ˣ.(1 + 3) + 64 = 4.25
3ˣ.4 + 64 = 100
3ˣ.4 = 100 - 64
3ˣ.4 = 36
3ˣ = 36 : 4
3ˣ = 9
3ˣ = 3²
x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a)39 . 213 + 87 . 39
=39 . (213 + 87 )
=39 . 300
= 11700
b)27 . 75 + 25 . 27 - 150
=27 . (75 + 25) - 150
=27 . 100 - 150
= 2700 - 150
= 2550
a) Ta có: \(39.213+87.39=39.\left(213+87\right)\)
\(=39.300\)
\(=11700\)
b) Ta có: \(27.75+25.27-150=27.\left(75+25\right)-150\)
\(=27.100-150\)
\(=2700-150\)
\(=2550\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(12x-33=3^2.3^3\)
\(\Rightarrow12x-33=3^5\)
\(\Rightarrow12x-33=243\)
\(\Rightarrow12x=243+33\)
\(\Rightarrow12x=276\)
\(\Rightarrow x=276:12\)
\(\Rightarrow x=23\)
tíc mình nha
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a) `123 - 27 + 27 + 13 - 123`
`= (123 - 123) + (27 - 27) + 13`
`= 0 + 0 + 13`
`= 13`
`---`
b) `175 + 25 + 13 + 15 - 175 - 25`
`= (175-175)+(25-25)+25+13`
`=0+0+25+13`
`=28`
`---`
c) \(53\times39+47\times39+53\times21+47\times21\)
\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)
\(=\left(100\times39\right)+\left(100\times21\right)\)
\(=3900+2100\)
`=6000`
`---`
d) \(49\times35+49\times16-49\times61\)
`=` \(49\times\left(35+16-61\right)\)
`=` \(49\times\left(-10\right)\)
`=-490`
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 42x99-21x176-35x12
=4158-3696-420
=42
b){[213^0+(999-998)^324]x2-12x5}-4^9:4^6
={[1+1^324]x2-60}-4^3
={[1+1]x2-60}-64
={2x2-60}-64
={4-60}-64
=-56-64
=-120
c)|-27|+(-25)-(-13)
=27+(-25)+13
=2+13
=15
![](https://rs.olm.vn/images/avt/0.png?1311)
27 . 75 + 25 . 27 - 150
= 27 . ( 75 + 25 ) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 27 . 75 + 25 . 27 - 150 = 2025 + 675 - 150 = 2700 - 150 = 2550.
Lưu ý. Có thể dùng tính chất phân phối của phép nhân đối với phép cộng để nhẩm:
27 . 75 + 25 . 27 - 150 = 27 . (75 + 25) - 150 = 27 . 100 - 150 = 2700 - 150 = 2550.
b) 12 : {390 : [500 - (125 + 35 . 7)]} = 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)] = 12 : (390 : 130) = 12 : 3 = 4.
a,27+75.25+27-150
= 27.(75+25)-150
=27.100-150
=2700-150
=2550
b,12:{390:[500-(125+35.7)]}
=12:{390:[500-(125+245)]}
=12:{390:[500-370]}
=12:{390:130}
=12:3
=4
Thank you very much
a, 39 x 213 + 87 x 39
= 39 x ( 213 + 87)
= 39 x 300
= 11700
b. 27 x 75 + 25 x 27 - 150
= 27 x ( 75 + 25 ) - 150
= 27 x 100 - 150
= 2700 - 150
= 2550
a) 39 x 213 + 87 x 39
= 39 x ( 213 + 87 )
= 39 x 300
= 11700
b) 27 x 75 + 25 x 27 - 150
= 27 x ( 75 + 25 ) - 150
= 27 x 100 - 150
= 2700 - 150
= 2550