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ƯC của(−15;+20) là: {±1;±5}
đây là theo hiểu biết của mk thôi nha, ko chép ai đâu^^
1: \(\left(416-7654\right)-\left(-584+19-654\right)\)
\(=416-7654+584-19+654\)
\(=416+584-7654+654-19\)
=1000-7000-19
=-6019
2: \(\left(214-4864\right)-\left(-192+4214-865\right)\)
\(=214-4864+192-4214+865\)
\(=\left(214-4214\right)+\left(-4864+865\right)+192\)
\(=-4000-4864+864+1+192\)
\(=-4000-4000+193=-8193\)
3: \(\left(-324+1756\right)-\left(2023-4324+756\right)\)
\(=-324+1756-2023+4324-756\)
\(=\left(-324+4324\right)+\left(1756-756\right)-2023\)
\(=4000+1000-2023=5000-2023=2977\)
4: \(\left(-214-248\right)-\left(-695+486-1248\right)\)
\(=-214-248+695-486+1248\)
\(=\left(1248-248\right)+\left(-486-214\right)+695\)
\(=1000-700+695=300+695=965\)
5: \(\left(-46+2198\right)-\left(-2023-146+198\right)\)
\(=-46+2198+2023+146-198\)
\(=\left(-46+146\right)+\left(2198-198\right)+2023\)
\(=2000+100+2023=2100+2023=4123\)
6: \(\left(-416+25\right)-\left(-1416+17-475\right)\)
\(=-416+25+1416-17+475\)
\(=\left(1416-416\right)+\left(475+25\right)-17\)
\(=1000+500-17=1500-17=1483\)
7: \(\left(-253+1976-41\right)-\left(447+976-241\right)\)
\(=-253+1976-41-447-976+241\)
\(=\left(-253-447\right)+\left(1976-976\right)+\left(241-41\right)\)
\(=-700+1000+200=500\)
8: \(-\left(-195+24-687\right)+\left(424-6195\right)\)
\(=195-24+687+424-6195\)
\(=\left(195-6195\right)+\left(424-24\right)+687\)
\(=-6000+400+687=-6000+1087=-4913\)
9: \(-\left(-241+95-148\right)-\left(6241+305\right)\)
\(=241-95+148-6241-305\)
\(=\left(241-6241\right)+\left(-95-305\right)+148\)
=-6000-400+148
=-6400+148=-6252
Bài 5:
Gọi số sách là x
Theo đề, ta có: \(x\in BC\left(8;12;15\right)\)
hay x=480
a, \(\dfrac{4x}{7}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}\Rightarrow60x=91\Leftrightarrow x=\dfrac{91}{60}\)
b, \(\dfrac{4}{5}+\dfrac{5}{7x}=\dfrac{1}{6}\Rightarrow\dfrac{5}{7x}=-\dfrac{19}{30}\Rightarrow7x\left(-19\right)=150\Leftrightarrow x=\dfrac{150}{7\left(-19\right)}=-\dfrac{150}{133}\)
a: =>4/7x=1/5+2/3=3/15+10/15=13/15
hay x=91/60
b: =>5/7:x=1/6-4/5=-19/30
hay x=-150/133
Các cạnh bằng nhau: MN = QP ;NP = MQ
Các cạnh song song: MN // QP ;NP // MQ
Các góc bằng nhau:
góc NMQ = góc MQP ;góc NMQ = góc QPN ;góc NMQ = góc PNM
góc MQP = góc QPN ;góc MQP = góc PNM
góc QPN = góc PNM
a: 3x+21=57
=>3x=57-21
=>3x=36
=>\(x=\dfrac{36}{3}=12\)
b: \(2x-138=2^3\cdot3^2\)
=>\(2x-138=8\cdot9=72\)
=>2x=72+138=210
=>x=105
c: \(4x^3+12=120\)
=>\(4x^3=120-12=108\)
=>\(x^3=27=3^3\)
=>x=3
\(a)3x+21=57\\ \Leftrightarrow3x=57-21\\ \Leftrightarrow3x=36\\ \Leftrightarrow x=\dfrac{36}{3}\\ \Leftrightarrow x=12\\ b)2x-138=2^3\cdot3^2\\ \Leftrightarrow2x-138=72\\ \Leftrightarrow2x=72+138\\ \Leftrightarrow2x=210\\ \Leftrightarrow x=\dfrac{210}{2}\\ \Leftrightarrow x=105\\ c)4x^3+12=120\\ \Leftrightarrow4x^3=120-12\\ \Leftrightarrow4x^3=108\\ \Leftrightarrow x^3=\dfrac{108}{4}\\ \Leftrightarrow x^3=27\\ \Leftrightarrow x^3=3^3\\ \Leftrightarrow x=3.\)
Ta có: (x.y+2x) + 10y+19 = 0
x(y+2) + 10(y+2) = 0+1 = 1
(y+2)(x+10) = 1
jjkklh