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phần bù đến 1 của 21/31 là: 1-21/31=10/31
phần bù đến 1 của 217/317 là:1-217/317=100/317
ta có 10/31=100/310
vì 100/310>100/317 nên 10/31>100/317 => 21/31<217/317 => A<B
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{{ - 21}}{{10}}\) < 0
b) \(\frac{{ - 5}}{{ - 2}} = \frac{5}{2} > 0\). Vậy \(\frac{{ - 5}}{{ - 2}} > 0\).
c) \(\frac{{ - 5}}{{ - 2}} = \frac{5}{2} > 0\), mà \(\frac{{ - 21}}{{10}} < 0\)
Vậy \(\frac{{ - 5}}{{ - 2}} > \frac{{ - 21}}{{10}}\).
a: \(-\dfrac{21}{10}< 0\)
b: \(0< -\dfrac{5}{-2}\)
c: \(-\dfrac{21}{10}< 0< \dfrac{-5}{-2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\Rightarrow2A=2+2^2+...+2^{2011}\)
\(\Rightarrow2A-A=2+2^2+...+2^{2011}-2^0-2-..-2^{2010}\)
\(\Rightarrow A=2^{2011}-1=B\)
\(b,A=2019.2011=\left(2010-1\right)\left(2010+1\right)=\left(2010-1\right).2010+\left(2010-1\right)=2010^2-2010+2010-1=2010^2-1< 2010^2=B\)
\(a,\Rightarrow2A=2^1+2^2+...+2^{2011}\\ \Rightarrow2A-A=A=2^{2011}-2^0=2^{2011}-1=B\)
\(b,A=\left(2010-1\right)\left(2010+1\right)=2010^2+2010-2010-1=2010^2-1< 2010^2=B\)
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a) Ta so sánh \(\frac{214}{317}\)và \(\frac{21}{38}\)
Có \(\frac{21}{38}=\frac{189}{342}\)
Cũng có \(\frac{214}{317}+1=\frac{531}{317};\frac{189}{342}+1=\frac{531}{342}\)
=) \(\frac{531}{317}>\frac{531}{342}\)=) \(\frac{214}{317}+1>\frac{189}{342}+1\)=) \(\frac{214}{317}>\frac{189}{342}\)
=) \(\frac{214}{317}>\frac{21}{38}\)=) \(\frac{-214}{317}< \frac{-21}{38}\)
b) Có : \(\frac{-6}{17}=\frac{-12}{34};\frac{4}{-13}=\frac{-4}{13}=\frac{-12}{39}\)
=) \(\frac{-12}{34}< \frac{-12}{39}\)=) \(\frac{-6}{17}< \frac{4}{-13}\)
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a: \(11^{14}< 11^{15}\)
b: \(4^{300}=64^{100}\)
\(3^{400}=81^{100}\)
mà 64<81
nên \(4^{300}< 3^{400}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Có 3 = (3
)
= 9
và 2
= (2
)
= 8
=> 3
> 2
b, Có 6 = (6
)
= 36
=> 6
> 12
37,37 x 5959,59 = 37 x 1,01 x 59 x 101,01 = 37 x 59 x 1,01 x 101,01
59,59 x 3737,37 = 59 x 1,01 x 37 x 101,01 = 37 x 59 x 1,01 x 101,01
=> 37,37 x 5959,59 = 59,59 x 3737,37
Kick mik nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{-15}{17}=-1+\dfrac{2}{17}\\ -\dfrac{19}{21}=-1+\dfrac{2}{21}\\ Vì:\dfrac{2}{17}>\dfrac{2}{21}\Rightarrow-1+\dfrac{2}{17}>-1+\dfrac{2}{21}\Rightarrow-\dfrac{15}{17}>-\dfrac{19}{21}\\ b,-\dfrac{24}{35}=-1+\dfrac{11}{35};-\dfrac{19}{30}=-1+\dfrac{11}{30}\\ Vì:\dfrac{11}{35}< \dfrac{11}{30}\Rightarrow-1+\dfrac{11}{35}< -1+\dfrac{11}{30}\\ \Rightarrow-\dfrac{24}{35}< -\dfrac{19}{30}\)
Ta có:
\(A=\frac{21}{31}=\frac{210}{310}=1-\frac{100}{310}\)
\(B=\frac{217}{317}=1-\frac{100}{317}\)
Vì \(\frac{100}{310}>\frac{100}{317}\)=> \(1-\frac{100}{310}< 1-\frac{100}{317}\)
=> \(A< B\)