Question

[masrur]

So sánh tổng S=\(\frac{1}{5}\)+\(\frac{1}{9}\)+\(\frac{1}{10}\)+\(\frac{1}{41}\)+\(\frac{1}{42}\) với \(\frac{1}{2}\)

Answer 1

[Sửu Nhi]

S<1/2 nha bạn

Answer 2

[Võ Đông Anh Tuấn]

S = \(\frac{1}{5}+\frac{1}{9}+\frac{1}{10}+\frac{1}{41}+\frac{1}{42}=\frac{5932}{12915}=0.459310878\approx0.45\)

\(\frac{1}{2}=0.5\)

Vì 0.45 < 0.5

\(\Leftrightarrow\) S < 1/2