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\(\left(x+y-z\right)^2+2.\left(x+y-z\right).\left(z-y\right)+\left(y-z\right)^2=\left[\left(x+y-z\right)+\left(z-y\right)\right]^2=x^2\)
Sai đề.
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![](https://rs.olm.vn/images/avt/0.png?1311)
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Ta có: x+y+z=0
\(\Leftrightarrow\left(x+y+z\right)^2=0\)
\(\Leftrightarrow x^2+y^2+z^2+2xy+2yz+2xz=0\)(1)
Ta có: \(K=\dfrac{x^2+y^2+z^2}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
\(=\dfrac{x^2+y^2+z^2}{x^2-2xy+y^2+y^2-2yz+z^2+z^2-2xz+x^2}\)
\(=\dfrac{x^2+y^2+z^2}{3x^2+3y^2+3z^2-x^2-y^2-z^2-2xy-2yz-2xz}\)
\(=\dfrac{x^2+y^2+z^2}{3\left(x^2+y^2+z^2\right)-\left(x^2+y^2+z^2+2xy+2yz-2xz\right)}\)
\(=\dfrac{x^2+y^2+z^2}{3\left(x^2+y^2+z^2\right)}=\dfrac{1}{3}\)
Vậy: \(K=\dfrac{1}{3}\)
\(K=\dfrac{x^2+y^2+z^2}{2\left(x^2+y^2+z^2\right)-2\left(xy+yz+zx\right)}\)
\(K=\dfrac{x^2+y^2+z^2}{3\left(x^2+y^2+z^2\right)-\left(x+y+z\right)^2}=\dfrac{1}{3}\)
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a) \(=x^2+2xy+y^2+x^2-2xy+y^2=2\left(x^2+y^2\right)\)
b) \(=2\left(x^2-y^2\right)+2\left(x^2+y^2\right)=2x^2+2x^2+2y^2-2y^2=4x^2\)( cái này áp dụng luôn kết quả câu trên nha)
c) \(\left(x-y+z\right)^2++2\left(x-y+z\right)\left(y-z\right)+\left(y-z\right)^2=\left(x-y+z+y-z\right)^2=x^2\)
tớ cũng giống Nguyễn Thị Bích Hậu
tích cho nha 1 cái thôi cũng được .
![](https://rs.olm.vn/images/avt/0.png?1311)
Dùng hằng đẳng thức thứ 2:
A= [(x+y+z)-(x+y)]2=z2
Chúc bạn học tốt!
Áp dụng HĐT thứ 2: (A - B)2 = A2 - 2AB + B2, ta có:
(x + y + z)2 - 2(x + y + z)(x + y) + (x + y)2 = [(x + y + z) - (x + y)]2
= z2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(a\right):\left(x+y\right)^2-\left(x-y\right)^2=x^2+2xy+y^2-\left(x^2-2xy+y^2\right)\\ =x^2+2xy+y^2-x^2+2xy-y^2\\ =4xy\)
\(\left(b\right):\left(x-y-z\right)^2+\left(x+y+z\right)^2\\ =\left[\left(x-y\right)-z\right]^2+\left[\left(x+y\right)+z\right]^2\\ =\left(x-y\right)^2-2z\left(x-y\right)+z^2+\left(x+y\right)^2+2z\left(x+y\right)+z^2\\ =x^2-2xy+y^2-2xz+2yz+z^2+x^2+2xy+y^2+2xz+2yz+z^2\\ =2x^2+2y^2+2z^2+4yz\)
\(\left(c\right):\left(x+y\right)^2-2\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\\ =\left[\left(x+y\right)-\left(x-y\right)\right]^2\\ =\left(x+y-x+y\right)^2\\ =\left(2y\right)^2=4y^2\)
(x + y + z)2 – 2.(x + y + z).(x + y) + (x + y)2
= [(x + y + z) – (x + y)]2 (Áp dụng HĐT (2) với A = x + y + z ; B = x + y)
= z2.