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A, \(\dfrac{7}{9}\) = \(\dfrac{7\cdot5}{9\cdot5}\) = \(\dfrac{35}{45}\) \(\dfrac{3}{5}\) = \(\dfrac{3\cdot9}{5\cdot9}\) = \(\dfrac{27}{45}\)
Vậy \(\dfrac{7}{9}\) > \(\dfrac{3}{5}\)
B, \(\dfrac{3}{4}\) = \(\dfrac{3\cdot6}{4\cdot6}\) = \(\dfrac{18}{24}\) \(\dfrac{5}{6}\) = \(\dfrac{5\cdot4}{6\cdot4}\) = \(\dfrac{20}{24}\)
Vậy \(\dfrac{3}{4}\) < \(\dfrac{5}{6}\)
C, \(\dfrac{1}{4}\) = \(\dfrac{1\cdot3}{4\cdot3}\) = \(\dfrac{3}{12}\) \(\dfrac{2}{3}\) = \(\dfrac{2\cdot4}{3\cdot4}\) = \(\dfrac{8}{12}\)
Vậy \(\dfrac{1}{4}\) < \(\dfrac{2}{3}\)
D, \(\dfrac{8}{9}\) = \(\dfrac{8\cdot2}{9\cdot2}\) = \(\dfrac{16}{18}\) \(\dfrac{1}{2}\) = \(\dfrac{1\cdot9}{2\cdot9}\) = \(\dfrac{9}{18}\)
Vậy \(\dfrac{8}{9}\) > \(\dfrac{1}{2}\)
\(\cdot\) là dấu nhân
\(a,\dfrac{1}{4},\dfrac{5}{6}và\dfrac{7}{12}\)
\(\dfrac{1}{4}=\dfrac{1\times3}{4\times3}=\dfrac{3}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12};\dfrac{7}{12}\)
\(b,\dfrac{1}{9},\dfrac{3}{5},\dfrac{11}{45}\)
\(\dfrac{1}{9}=\dfrac{1\times5}{9\times5}=\dfrac{5}{45};\dfrac{3}{5}=\dfrac{3\times9}{5\times9}=\dfrac{27}{45};\dfrac{11}{45}\)
\(\frac{3}{5}=\frac{3\times8}{5\times8}=\frac{24}{40}\)
\(\frac{3}{8}=\frac{3\times5}{8\times5}=\frac{15}{40}\)
\(\frac{3}{10}=\frac{3\times4}{10\times4}=\frac{12}{40}\)
\(\frac{3}{2}=\frac{3\times20}{2\times20}=\frac{60}{40}\)
Ta có:
\(\frac{2}{5}=\frac{8}{20};\frac{4}{2}=\frac{40}{20};\frac{6}{2}=\frac{60}{20};\frac{9}{4}=\frac{45}{20};\frac{5}{4}=\frac{25}{20}\)
Vì \(\frac{8}{20}
\(\frac{3}{5}=\frac{24}{40};\frac{3}{8}=\frac{15}{40};\frac{3}{10}=\frac{12}{40};\frac{3}{2}=\frac{60}{40}\)
\(\frac{3}{5}=\frac{3\times8}{5\times8}=\frac{24}{40}\)
\(\frac{3}{8}=\frac{3\times5}{8\times5}=\frac{15}{40}\)
\(\frac{3}{10}=\frac{3\times4}{10\times4}=\frac{12}{40}\)
\(\frac{3}{2}=\frac{3\times20}{2\times20}=\frac{60}{40}\)
MSC:60
\(\dfrac{1}{2}=\dfrac{1\times30}{2\times30}=\dfrac{30}{60}\); \(\dfrac{2}{3}=\dfrac{2\times20}{3\times20}=\dfrac{40}{60}\); \(\dfrac{3}{4}=\dfrac{3\times15}{4\times15}=\dfrac{45}{60}\); \(\dfrac{17}{10}=\dfrac{17\times6}{10\times6}=\dfrac{102}{60}\)
\(\dfrac{1}{2}=\dfrac{30}{60}\)
\(\dfrac{2}{3}=\dfrac{40}{60}\)
\(\dfrac{3}{4}=\dfrac{45}{60}\)
\(\dfrac{17}{10}=\dfrac{102}{60}\)
A) \(\frac{5}{12};\frac{2}{3};\frac{3}{4}\)
B)\(\frac{11}{30};\frac{2}{5};\frac{5}{6}\)
a) \(\frac{5}{12};\frac{2}{3};\frac{3}{4}\)
b)\(\frac{5}{6};\frac{2}{5};\frac{11}{30}\)
~HT~
Bài 3 :
a: \(MSC:12\\ \dfrac{4}{3}=\dfrac{4\times4}{3\times4}=\dfrac{16}{12};\dfrac{3}{4}=\dfrac{3\times3}{3\times4}=\dfrac{9}{12}\)
b: \(MSC:12\\ \dfrac{5}{4}=\dfrac{5\times3}{4\times3}=\dfrac{15}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
c:\(MSC:24\\ \dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24};\dfrac{1}{6}=\dfrac{1\times2}{6\times2}=\dfrac{2}{12}\)
d: \(MSC:35\\ \dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{4}{7}=\dfrac{4\times5}{7\times5}=\dfrac{20}{35}\)
Bài 3:
a: 4/3=16/12
3/4=9/12
b: 5/4=30/24
5/6=20/24
c: 3/8=18/48
1/6=8/48
d: 2/5=14/35
4/7=20/35
Bài 4:
a: 7/12=28/48
5/48=5/48
b: 4/100=4/100
8/25=32/100
TL
1/4=1x6x3/4x6x3=18/72
5/6=5x4x3/6x4x3=60/72
2/3=2x6x4/3x6x4=48/72
nha
HT