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S2=(1+2+2^2+2^3+...+2^62+2^63)*2
=2+2^2+2^3+...+2^63+2^64
S2-S= (2+2^2+2^3+...+2^63+2^64) - (1+2+2^2+2^3+...+2^62+2^63)
S = 2^64 - 1
S=1+2+22+...+262+263
2S=2+22+23+...+263+264
2S+1=1+2+22+...+263+264=S+264
2S-S=264-1
Vậy S=264-1
S=1+2+22+23+...+262+263
2S=2+22+23+24+...+263+264
2S-S=264-1
S=264-1
S = 1 + 2 + 22 + 23 + 24 + ... + 262 + 263
2S = 2 . ( 1 + 2 + 22 + 23 + 24 + ... + 262 + 263 )
2S = 2 + 22 + 23 + 24 + 25 + ... + 263 + 264
2S - S = 2 + 22 + 23 + 24 + 25 + ... + 263 + 264 - ( 1 + 2 + 22 + 23 + 24 + ... + 262 + 263 )
S = 264 - 1
Vậy S = 264 - 1
\(S=1+2+2^2+2^3+.....+2^{62}+2^{63}\)
\(2S=2+2^2+2^3+2^4+....+2^{63}+2^{64}\)
\(2S-S=2+2^2+2^3+2^4+.....+2^{63}+2^{64}-\left(1+2+2^2+2^3+.....+2^{62}+2^{63}\right)\)
\(S=2^{64}-1\)
Giải
S=1+2+22+23+....................+262+263
2S=2(1+2+22+23+.................+262+263)
2S=2+22+23+24+............................+263+264)
2S-S=(2+22+23+24+...................+263+264)-(1+2+22+23+.....................+262+263)
S=264-1
Ta có:\(2^{64}-1=\left(2-1\right)\left(2^{63}+2^{62}+2^{61}+...+1\right)\)
Do đó S\(=2^{64}-1\)
Ngắn gọn quá phải không dùng hđt:\(a^n-b^n\)
A=1+2+22+23+...+262+263
2A=2+22+23+24+...+263+264
2A-A=2+22+23+24+...+263+264-1+2+22+23+...+262+263
A=264-1
\(A=1+2+2^2+2^3+..+2^{62}+2^{63}\)
\(2A=2+2^2+2^3+...+2^{63}+2^{64}\)
\(2A-A=2^{64}-1\)
\(A=2^{64}-1\)