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a) 3. 5 ^ 2 + 15. 2 ^2 - 26 : 2
= 15 ^ 2 + 15. 4 - 13
= 225 + 60 - 13
= 272
b) 5 ^ 3. 2 - 100 : 4 + 2 ^ 3. 5
= 125. 2 - 25 + 40
= 250 - 25 + 40
= 265
c) 6 ^ 2 : 9 + 50. 2 - 3 ^ 3. 3
= 36 : 9 + 100 - 81
= 4 + 100 - 81
= 23
d) 3 ^ 2. 5 + 2 ^ 3 . 10 - 81 : 3
= 45 + 8 . 10 - 27
= 53 + 80 - 27
= 160
e) 5 ^ 13 : 5 ^ 10 - 25. 2 ^ 2
= 1220703125 : 9765625 - 25. 4
= 125 - 100
= 25
f) 20 : 2 ^ 2 + 5 ^ 9 : 5 ^ 8
= 20 : 4 + 1953125 : 390625
= 5 + 5
= 10
g) 100 : 5 ^ 2 + 7. 3 ^ 2
= 100 : 25 + 7 . 9
= 4 + 63
= 67
h) 84 :4 + 3 ^ 9 : 3 ^ 7 + 5 ^ 0
= 21 + 19683 : 2187 + 1
= 21 + 9 + 1
= 31
i) 29 - [ 16 + 3. ( 51 - 49) ]
= 29 - [ 16 + 3. 2 ]
= 29 - 22
= 7
Mình làm xong rồi nhé!
a)73+86+968+914+3032
= (86 + 914) +(968 + 3032) + 73
= 1000 + 4000 + 73
= 5073
b)341.67+341.16+659.83
=341 (67 + 16) + 659 * 83
= 341 * 83 + 659 * 83
= (341+ 659) * 83
= 1000 * 83
= 830000
c)252-84:21+7
= 252 - 2 +7
=257
d)4.8.25.125.27
= (8 * 125) (4* 25) * 27
= 1000 * 100 * 27
= 2700000
e)34+35+36+37-24-25-26-27
= (34-24) + (35-25) + (36-26) + (37-27)
= 10 + 10 + 10 + 10
= 40
g)1-2+3-4+...-98+99
= (1 + 99) + (-2-98) + .....+ (-48 - 52) + (49 + 51) - 50
= 100 - 50
= 50
h)1-4+7-10+...-100+103
Bài 2:Tìm số nguyên x,biết:
l)3636:(12.x-91)=36
3636 : (12x - 91) = 36
12x - 91 = 101
12x = 192
x= 16
m)(x:23+45).67=8911
x: 23 + 45 = 133
x : 23 = 88
x= 88/23
n)[(6.x-39):7].4=12
6x - 39 = 3
6x = 42
x=7
p)128-3(x+4)=23
3(x+4) = 105
x+4= 35
x= 31
q)[(4.x+28).3+55]:5=35
(4x + 28)*3 +55 = 175
(4x + 28) * 3 = 120
4x + 28 = 40
4x = 12
x=3
r)123-5.(x+4)=38
5(x+4) = 85
x+4 = 17
x= 13
t)11-(53+x)=97
53 + x = -86
x= -139
i)23.75+25.23+180
= 23(75+25) + 180
= 2300 + 180
= 2480
a; - \(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) - (- \(\dfrac{1}{6}\)) + (- \(\dfrac{2}{5}\))
= - \(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) + \(\dfrac{1}{6}\) - \(\dfrac{2}{5}\)
= \(-\dfrac{40}{60}\) + \(\dfrac{45}{60}\) + \(\dfrac{10}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{5}{60}\) + \(\dfrac{10}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{15}{60}\) - \(\dfrac{24}{60}\)
= - \(\dfrac{3}{20}\)
b; (- \(\dfrac{2}{3}\)) + (- \(\dfrac{1}{5}\)) + \(\dfrac{3}{4}\) - \(\dfrac{5}{6}\) - \(\dfrac{-7}{10}\)
= - \(\dfrac{2}{3}\) - \(\dfrac{1}{5}\) + \(\dfrac{3}{4}\) - \(\dfrac{5}{6}\) + \(\dfrac{7}{10}\)
= - \(\dfrac{40}{60}\) - \(\dfrac{12}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{50}{60}\) + \(\dfrac{42}{60}\)
= - \(\dfrac{52}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{50}{60}\) + \(\dfrac{42}{60}\)
= - \(\dfrac{7}{60}\) - \(\dfrac{50}{60}\) + \(\dfrac{42}{60}\)
= - \(\dfrac{57}{60}\) + \(\dfrac{42}{60}\)
= - \(\dfrac{1}{4}\)
Bài 1 :
a ) ( 2x + 1 )3 = 9.81
( 2x + 1 )3 = 729
( 2x + 1 )3 = 93
=> 2x + 1 = 9
2x = 9-1 = 8
x = 8 : 2 = 4
Vậy x = 4
b ) ( 7x - 11 )3 = 25 . 52 + 200
( 7x - 11 )3 = 32 . 25 + 200
( 7x - 11 )3 = 1000
( 7x - 11 )3 = 103
=> 7x - 11 = 10
7x = 10 + 11 = 21
x = 21 : 7 = 3
Vậy x = 3
Bài 2 :
a ) 50 - [ 30.( 6-2 )2 ]
= 50 - [ 30. 42 ]
= 50 - [ 30. 16 ]
= 50 - 480
= -430
b ) Tương tự
Bài 3 :
Câu hỏi của Phạm Ngọc Thạch - Toán lớp 6 - Học toán với OnlineMath
Link : https://olm.vn/hoi-dap/detail/6230029528.html
a) 43.27 - 43.23
= 43.(27-23)
= 43.4
= 44
b) 35.77+23.35+53.23
= 35.(77+23) + (5.2)3
= 35.100 + 103
= 35.102+ 102.10
= 102.(35+10)
= 100.45
= 4500
c) 32.5 + 23.10 - 81 : 3
= 9.5 + 8.2.5 - 27
= 5.(9+8.2) - 27
= 5.25 - 27
= 53 - 27
= 98
d) 151-291:288+13.3
= 151 - 23+3
= 151 - 8 + 3
= 146