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a: \(\dfrac{5}{7}=\dfrac{5\cdot11}{7\cdot11}=\dfrac{55}{77}\)
\(\dfrac{9}{11}=\dfrac{9\cdot7}{11\cdot7}=\dfrac{63}{77}\)
b: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot9}{7\cdot9}=\dfrac{54}{63}\)
\(-\dfrac{12}{54}=\dfrac{-2}{9}=\dfrac{-2\cdot7}{9\cdot7}=-\dfrac{14}{63}\)
c: \(\dfrac{-11}{30}=\dfrac{-11\cdot4}{30\cdot4}=\dfrac{-44}{120}\)
\(\dfrac{-17}{-40}=\dfrac{17}{40}=\dfrac{17\cdot3}{40\cdot3}=\dfrac{51}{120}\)
d: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot3}{7\cdot3}=\dfrac{18}{21}\)
\(\dfrac{-12}{36}=\dfrac{-1}{3}=\dfrac{-1\cdot7}{3\cdot7}=\dfrac{-7}{21}\)
Có thể chuyển thành 3 phân số: \(\frac{-3}{44};\frac{-11}{18};\frac{-5}{36}\)
_ Tìm \(BCNN\).
Ta có: \(BCNN\left(44;18;36\right)=396\)
_ Quy đồng mẫu số:
\(\frac{-3}{44}=\frac{-3.9}{44.9}=\frac{-27}{396}\)
\(\frac{-11}{18}=\frac{-11.22}{18.22}=\frac{-242}{396}\)
\(\frac{-5}{36}=\frac{-5.11}{36.11}=\frac{-55}{396}\)
Bài 4:
a: =>7/x-5=2
=>x-5=7/2
=>x=17/2
b: =>1-2x=-5
=>2x=6
=>x=3
c: =>2x-3=5 hoặc 2x-3=-5
=>2x=8 hoặc 2x=-2
=>x=-1 hoặc x=4
d: =>2(x+1)^2+17=21
=>2(x+1)^2=4
=>(x+1)^2=2
=>\(x+1=\pm\sqrt{2}\)
=>\(x=\pm\sqrt{2}-1\)
\(\dfrac{-54}{72}=\dfrac{-3}{4}\); \(\dfrac{42}{36}=\dfrac{7}{6}\); \(\dfrac{2}{-3}=\dfrac{2}{-3}\)
\(\Rightarrow BCNN\left(4,6,-3\right)=12\)
Quy đồng
\(\dfrac{-3}{4}=\dfrac{-3.3}{4.3}=\dfrac{-9}{12}\)
\(\dfrac{7}{6}=\dfrac{7.2}{6.2}=\dfrac{14}{12}\)
\(\dfrac{2}{-3}=\dfrac{2.\left(-4\right)}{\left(-3\right).\left(-4\right)}=\dfrac{-8}{12}\)