Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, \(\left(x^2+x\right)^2+9x^2+9x+14\)
\(=\left(x^2+x\right)^2+9\left(x^2+x\right)+14\)
\(=\left(x^2+x\right)^2+2\left(x^2+x\right)+7\left(x^2+x\right)+14\)
\(=\left(x^2+x\right)\left(x^2+x+2\right)+7\left(x^2+x+2\right)\)
\(=\left(x^2+x+2\right)\left(x^2+x+7\right)\)
b, \(x^2+2xy+y^2+2x+2y-15\)
\(=\left(x+y\right)^2+2\left(x+y\right)-15\)
\(=\left(x+y\right)^2+5\left(x+y\right)-3\left(x+y\right)-15\)
\(=\left(x+y\right)\left(x+y+5\right)-3\left(x+y+5\right)\)
\(=\left(x+y+5\right)\left(x+y-3\right)\)
Chúc bạn học tốt.
\(x^6-x^4-9x^3+9x^2\)
\(=x^6-x^5+x^5-x^4-9x^2\left(x-1\right)\)
\(=x^5\left(x-1\right)+x^4\left(x-1\right)-9x^2\left(x-1\right)\)
\(=\left(x-1\right)\left(x^5+x^4-9x^2\right)\)
\(x^6-x^4-9x^3+9x^2\)
\(=x^4.\left(x^2-1\right)-9x^2\left(x-1\right)\)
\(=x^4.\left(x-1\right)\left(x+1\right)-9x^2\left(x-1\right)\)
\(=\left(x-1\right)\left[x^4.\left(x+1\right)-9x^2\right]\)
x6 - x4 - 9x3 + 9x2
= x4.(x2 - 1) - 9x2.(x - 1)
= x4.(x - 1).(x + 1) - 9x2.(x - 1)
= (x - 1).(x5 + x - 9x2)
= (x - 1).x.(x4 + 1 - 9x)
x^6-x^4-9x^3+9x^2
=x^2(x^4-x^2-9x+9)
=x^2[x^2(x^2-1)-9(x-1)]
=x^2[x^2(x-1)(x+1)-9(x-1)]
=x^2(x-1)[x^2(x+1)-9)]
=x^2(x-1)(x+1)(x^2-9)
=x^2(x-1)(x+1)(x-3)(x+3)
a) \(x^2-9x+14\)
\(=x^2-2x-7x+14\)
\(=x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(x-7\right)\)
b) \(x^2+17x-18\)
\(=x^2+18x-x-18\)
\(=x\left(x+18\right)-\left(x+18\right)\)
\(=\left(x+18\right)\left(x-1\right)\)
c) \(2x^2-7x+3\)
\(=2x^2-x-6x+3\)
\(=x\left(2x-1\right)-3\left(2x-1\right)\)
\(=\left(2x-1\right)\left(x-3\right)\)
d) \(x^2-25x+144\)
\(=x^2-9x-16x+144\)
\(=x\left(x-9\right)-15\left(x-9\right)\)
\(=\left(x-9\right)\left(x-15\right)\)
(x2+2x)2+9x2+18x+20
=(x2+2x)2+9(x2+2x)+20
Đặt t=x2+2x ta được:
t2+9t+20=t2+4t+5t+20
=t.(t+4)+5.(t+4)
=(t+4)(t+5)
thay t=x2+2x ta được:
(x2+2x+4)(x2+2x+5)
Vậy (x2+2x)2+9x2+18x+20=(x2+2x+4)(x2+2x+5)
9x2-2015x+2006
= 9x2-9x-2006x+2006
= (9x2-9x)-(2006x-2006)
= 9x(x-1)-2006(x-1)
= (x-1) (9x-2006)
Chúc học tốt nhé!
\(\left(x^2+x\right)^2+9x^2+9x+14\)
= \(\left(x^2+x\right)^2-4+\left(9x^2+9x+18\right)\)
= \(\left(x^2+x\right)^2-2^2+9\left(x^2+x+2\right)\)
= \(\left(x^2+x+2\right)\left(x^2+x-2\right)+9\left(x^2+x+2\right)\)
= \(\left(x^2+x+2\right)\left(x^2+x+7\right)\)
Chúc bạn làm bài tốt!!!!!!
ai giúp mình với . ko bik có sai đề không chứ minh giải miết không ra