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\(x^2-y^2+10x-6y+16\)
\(=\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)
\(=\left(x+5\right)^2-\left(y+3\right)^2\)
\(=\left(x+5-y-3\right)\left(x+5+y+3\right)\)
\(=\left(x-y+2\right)\left(x+y+8\right)\)
d: \(=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)
x^2-y^2+10x-6y-9
=x^2+10x -(y^2+6y+9)
= x^2+10x-(y^2+2.3.y+3^2)
=x^2+10x-(y+3)^2
=\(\left[x^2-\left(y+3\right)^2\right]+10x \)
={\(\left(x+x+3\right)\left[x-\left(x+3\right)\right]\)}\(+10x\)
=\(\left(x+x+3\right).\left(x-x-3\right)+10x\)
(đến đây b tự lm nhé, m cx k bt đúng k nx )
Ta có: \(\left(x+y\right)\left(y+z\right)\left(z+x\right)+xyz=x^2y+xy^2+xyz+y^2z+yz^2+xyz+xz^2+x^2x+xyz\)
\(=xy\left(x+y+z\right)+yz\left(x+y+z\right)+zx\left(x+y+z\right)=\left(x+y+z\right)\left(xy+yz+zx\right)\)
\(x^2-y^2+10x-6y+16=\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)
\(=\left(x+5\right)^2-\left(y+3\right)^2=\left(x+y+8\right)\left(x-y+2\right)\)
\(x^2\left(y-z\right)+y^2\left(z-x\right)+z^2\left(x-y\right)=x^2\left(y-z\right)+yz\left(y-z\right)-x\left(y-z\right)\left(y+z\right)\)
\(=\left(y-z\right)\left(x^2+yz-xy-xz\right)=\left(y-z\right)\left(x-y\right)\left(z-x\right)\)
phân tích đa thức thành nhân tử
a, 6x^2 + 7xy + 2y^2
=6x^2+3xy+4xy+2y^2
=3x(x+y)+2y(x+y)
=(3x+2y)(x+y)
b, 9x^2 - 9xy - 4y^2
=9x^2 +3xy-12xy-4y^2
=3x(x+y)-4y(x+y)
=(3x+4y)(x+y)
c, x^2 - y^2 + 10x - 6y + 16=x^2-y^2+6x-6y+4x+16=x(x+6)-y(x+6)+4(x+6)=(x-y+4)(x+6)
Bài làm
a, 6x2 + 7xy + 2y2
= 6x2 + 3xy + 4xy + 2y2
= ( 6x2 + 3xy ) + ( 4xy + 2y2 )
= 3x( 2x + y ) + 2y( 2x + y )
= ( 2x + y )( 3x + 2y )
b, 9x2 - 9xy - 4y2
= 9x2 - 12xy + 3xy - 4y2
= ( 9x2 - 12xy ) + ( 3xy - 4y2 )
= 3x( 3x - 4y ) + y ( 3x - 4y )
= ( 3x + y )( 3x - 4y )
c, x2 - y2 + 10x - 6y + 16
= x2 - y2 - 6x + 6y + 4x + 16
= x( x + 6 ) - y( x + 6 ) + 4( x + 6 )
= ( x - y + 4 )( x + 6 )
# Học tốt #
\(10x\left(x-y\right)-8y\left(y-x\right)\)
\(=10x\left(x-y\right)+8y\left(x-y\right)\)
\(=\left(x-y\right)\left(10x+8y\right)\)
\(=2\left(x-y\right)\left(5x+4y\right)\)
a) 8x2-2x-1=8x2+4x-2x-2x-1=(8x2+4x)-(2x+1)=4x.(2x+1)-(2x+1)=(2x+1).(4x-1)
b) x2-y2+10x-6y+16x=x2-y2+10x+10y-16y+16x=(x-y)(x+y)+10(x+y)-16(y+x)=(x+y)(x-y+10+16)
`#3107.101107`
`x^2 - y^2 + 10x - 10y`
`= (x^2 - y^2) + (10x - 10y)`
`= (x - y)(x + y) + 10(x - y)`
`= (x + y + 10)(x - y)`
_____
Sử dụng HĐT:
`A^2 - B^2 = (A - B)(A + B).`
= 10x ( x - y ) + 6y ( x - y )
= ( x - y ) ( 10x + 6 y )
= 2 ( x - y ) ( 5x + 3y )
10x(x-y)-6y(y-x)
=10x(x-y)+6y(x-y)
=(x-y)(10x+6y)