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26 tháng 8 2019

1, 5a2xy-10a3x-15ay = 5a( axy - 2a\(^2\)x - 3y )

2, mxy-m2x+my = m( xy - mx + y )

3, 2mx-4m2xy+6mx = 2mx( 1 - 2my + 3 ) = 2mx( 4 - 2my )

4, a2b-2ab2+ab = ab( a - 2b + 1 )

5, 5a2b-2ab2+ab = ab( 5a - 2b +1 )

6, -3x2y3-6x3y2-x2y2 = -3x\(^2\)y\(^2\) ( y + 2x + 1 )

7, 5x2y4-10x4y2+5x2y2 = 5x\(^{^2y^2}\)( y\(^2\) - 2x\(^2\) + 1 )

8, -2x3y4-4x4y3+2x3y3 = 2\(x^3y^3\) ( -y - 2x + 1 )

9, 4x3y2-8x3y+16xy2-24 = 4( x\(^3\)y\(^2\) - 2x\(^3\)y + 4 xy\(^2\) - 6 )

10, 12x3y-6xy+3x = 3x( 4x\(^2\)y - 2y + 1 )

11, 2(x-y)-a(x-y) = ( 2 - a ) ( x - y )

12, a(x-y)+b(x-y)= ( a + b ) ( x - y )

13, m(x+y)-n(x+y) = ( m - n ) ( x + y )

14, 2a(x+y)-4(x+y) = ( 2a - 4 )( x + y ) = 2( a - 2 ) ( x + y )

15, 3a(x+y)-6ab(x+y) = ( 3a - 6ab )( x + y ) = 3a( 1 - 2b ) ( x + y )

16, 5a2(x-y)+10a(x-y) = ( 5a\(^2\)+10a )( x - y ) = 5a( a + 2 ) ( x - y )

17, -2ab(x-y)-4a(x-y) = ( -2ab - 4a )( x - y ) = -2a( b + 2 )( x - y )

18, 3a(x-y)+2(x-y) = ( 3a + 2 ) ( x - y )

19, m(a-b)-m2(a-b) = ( m - m\(^2\) ) ( a - b ) = m( 1 - m ) ( a - b )

20, mx(a+b)-m(a+b) = ( mx - m ) ( a + b ) = m( x - 1 )( a + b )

21, x(a-b)-y(b-a) = x( a - b ) + y( a - b ) = ( x + y ) ( a - b )

22, ab(x-5)-a2(5-x) = ab( x - 5 ) + a\(^2\)( x - 5 ) = ( ab + a\(^2\) ) ( x - 5 ) = a( b + a )( x - 5 )

23, 2a2(x-y)-4a(y-x)= 2a\(^2\)( x - y ) + 4a( x - y )=( 2a\(^2\) + 4a ) ( x - y )= 2a( a + 2 )( x - y )

26 tháng 8 2019

Đăng ít thôi =))

a. \(5a^2xy-10a^3x-15ay=5a\left(axy-2a^2x-3y\right)\)

b. \(mxy-m^2x+my=m\left(xy-mx+y\right)\)

c. \(2mx-4m^2xy+6mx=2mx\left(1-2my+3\right)=2mx\left(-2my+4\right)\)

d. \(a^2b-2ab^2+ab=ab\left(a-2b+1\right)\)

e. \(5a^2b-2ab^2+ab=ab\left(5a-2b+1\right)\)

g.

2: \(8xy-24xy+16x\)

\(=8x\cdot y-8x\cdot3y+8x\cdot2\)

\(=8x\left(y-3y+2\right)=8x\left(-2y+2\right)\)

\(=-16y\left(y-1\right)\)

3: \(xy-x=x\cdot y-x\cdot1=x\left(y-1\right)\)

11: \(2mx-4m2xy+6mx\)

\(=2mx-2my\cdot4y+2mx\cdot3\)

\(=2mx\left(1-4y+3\right)\)

\(=2mx\left(4-4y\right)=8mx\left(1-y\right)\)

12: \(7x^2y^5-14x^3y^4-21y^3\)

\(=7y^3\cdot x^2y^2-7y^3\cdot2x^3y-7y^3\cdot3\)

\(=7y^3\left(x^2y^2-2x^3y-3\right)\)

13: \(2\left(x-y\right)-a\left(x-y\right)\)

\(=2\cdot\left(x-y\right)-a\cdot\left(x-y\right)\)

\(=\left(x-y\right)\left(2-a\right)\)

4 tháng 10 2020

a,\(2axy-4a^2xy^2+6a^3x^2\)

\(=2ax\left(y-2ay^2+3a^2x\right)\)

b,\(5a^2xy-10a^3x-15ay\)

\(=5a\left(axy-2ax-3y\right)\)

Tự lm tiếp, tất cả đều dùng bằng phương phép đặt nhân tử chung nhé

4 tháng 10 2020

23) \(2axy-4a^2xy^2+6a^3x^2\)

\(=2ax\left(y-2ay^2+3a^2x\right)\)

24) \(5a^2xy-10a^3x-15ay\)

\(=5a\left(axy-2a^2x-3y\right)\)

25) \(mxy-m^2x+my\)

\(=m\left(xy-mx+y\right)\)

26) \(2mx-4m^2xy+6mx\)

\(=2mx\left(1-2my+3\right)\)

\(=4mx\left(2-my\right)\)

2 tháng 8 2015

a,(x+y)(2a-4)

b,(x+y)(a-b)

c,a(b+a)(x-5)

d,2a(a+2)(x+y)

**** cho mk nha

2 tháng 8 2015

câu a ấy, làm chưa xong à?

28 tháng 8 2023

1) \(3x\left(x-1\right)+5\left(x-1\right)\)

\(=\left(x-1\right)\left(3x+5\right)\)

2) \(4x(x-2y)-8y(2y-x)\)

\(=4x\left(x-2y\right)+8y\left(x-2y\right)\)

\(=\left(4x+8y\right)\left(x-2y\right)\)

\(=4\left(x+2y\right)\left(x-2y\right)\)

3) \(a^2\left(x-1\right)+b^2\left(1-x\right)\)

\(=a^2\left(x-1\right)-b^2\left(x-1\right)\)

\(=\left(a^2-b^2\right)\left(x-1\right)\)

\(=\left(a-b\right)\left(a+b\right)\left(x-1\right)\)

4) \(3x\left(x-a\right)+4a\left(a-x\right)\)

\(=3x\left(x-a\right)-4a\left(x-a\right)\)

\(=\left(x-a\right)\left(3x-4a\right)\)

5) \(5x\left(x-y\right)^2+10y^2\left(y-x\right)^2\)

\(=5x\left(x-y\right)^2+10y^2\left(x-y\right)^2\)

\(=\left(5x+10y^2\right)\left(x-y\right)^2\)

\(=5\left(x+2y^2\right)\left(x-y\right)^2\)

6) \(3x\left(x-3\right)^2+9\left(3-x\right)^2\)

\(=3x\left(x-3\right)^2+9\left(x-3\right)^2\)

\(=\left(3x+9\right)\left(x-3\right)^2\)

\(=3\left(x+3\right)\left(x-3\right)^2\)

7) \(x\left(m-a\right)^2-y\left(a-m\right)^2\)

\(=x\left(a-m\right)^2-y\left(a-m\right)^2\)

\(=\left(x-y\right)\left(a-m\right)^2\)

8) \(6y^2\left(x-1\right)^2+9y\left(1-x\right)^2\)

\(=6y^2\left(x-1\right)^2+9y\left(x-1\right)^2\)

\(=\left(6y^2+9x\right)\left(x-1\right)^2\)

\(=3\left(2y^2+3x\right)\left(x-1\right)^2\)

#Ayumu

12 tháng 10 2021

\(1,\\ a,=4\left(x-2\right)^2+y\left(x-2\right)=\left(4x-8+y\right)\left(x-2\right)\\ b,=3a^2\left(x-y\right)+ab\left(x-y\right)=a\left(3a+b\right)\left(x-y\right)\\ 2,\\ a,=\left(x-y\right)\left[x\left(x-y\right)^2-y-y^2\right]\\ =\left(x-y\right)\left(x^3-2x^2y+xy^2-y-y^2\right)\\ b,=2ax^2\left(x+3\right)+6a\left(x+3\right)\\ =2a\left(x^2+3\right)\left(x+3\right)\\ 3,\\ a,=xy\left(x-y\right)-3\left(x-y\right)=\left(xy-3\right)\left(x-y\right)\\ b,Sửa:3ax^2+3bx^2+ax+bx+5a+5b\\ =3x^2\left(a+b\right)+x\left(a+b\right)+5\left(a+b\right)\\ =\left(3x^2+x+5\right)\left(a+b\right)\\ 4,\\ A=\left(b+3\right)\left(a-b\right)\\ A=\left(1997+3\right)\left(2003-1997\right)=2000\cdot6=12000\\ 5,\\ a,\Leftrightarrow\left(x-2017\right)\left(8x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2017\\x=\dfrac{1}{4}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-1\right)\left(x^2-16\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\\x=-4\end{matrix}\right.\)

28 tháng 11 2021
Lol .ngudoots
18 tháng 8 2017

chuyển về dạng nguyên thể rồi tính thể chất khối lượng sau đó quay về đang tìm mũ của nhiều số làm ra rồi thì dễ lắm bạn ạ k minh nha

18 tháng 8 2017

a)\(\left(x^2-2\right)\left(x^2+2x+2\right)\)

b)\(\left(x-1\right)\left(2x+1\right)\left(3x+7\right)\)

c)\(-2\left(x-4\right)\left(2x+1\right)\)

d)\(\left(x-5\right)\left(4x+1\right)\)

e)\(3\left(x-2\right)\left(3x-2\right)\)

g)\(2\left(a-b\right)^2\)

h)\(\left(xy-3\right)\left(5y^2-2z\right)\)

i)\(\left(4x+1\right)\left(2x-y\right)\)

l)\(abc^2\left(b-a\right)\left(b+c\right)\)

m)\(\left(x-y\right)\left(y-z\right)\left(x-z\right)\)