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-25.72+25.21-49.25
= -25.72 + (-25).(-21) - (-49).(-25)
= -25. [72+(-21)-(-49)]
= -25.100
= -2500
a) \(2.5^2.3^2+\left\{\left[2.5^3-\left(5x+4\right).5\right]:\left(2^2.3.5\right)\right\}=453\)
\(2.25.9+\left\{\left[2.125-\left(5x+4\right).5\right]:\left(4.3.5\right)\right\}=453\)
\(50.9+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(450+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(\left[250-\left(5x+4\right).5\right]:60=453-450\)
\(\left[250-\left(5x+4\right).5\right]:60=3\)
\(250-\left(5x+4\right).5=3.60\)
\(250-\left(5x+4\right).5=180\)
\(\left(5x+4\right).5=250-180\)
\(\left(5x+4\right).5=70\)
\(5x+4=70:5\)
\(5x+4=14\)
\(5x=14-4\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
Vậy \(x=2\)
b) \(\left|x-\frac{1}{3}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=-2\\x-\frac{1}{3}=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\left(-2\right)+\frac{1}{3}\\x=2+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{7}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{7};\frac{7}{3}\right\}\)
Bài 1:
a) \(\frac{13.23-13}{26.21+26}\)=\(\frac{13.22}{26.22}\)=\(\frac{13}{26}\)=\(\frac{1}{2}\)
b) \(\frac{16.21-16}{4.19+4}\)=\(\frac{16.20}{4.20}\)=\(\frac{16}{4}\)= 4
\(66:\left(2x-3\right)-22=0\Leftrightarrow66:\left(2x-3\right)=0+22\)
\(\Leftrightarrow66:\left(2x-3\right)=22\Leftrightarrow2x-3=66:22\Leftrightarrow2x-3=3\)
\(\Leftrightarrow2x=3+3\Leftrightarrow2x=6\Rightarrow x=6:2\Leftrightarrow x=3\)
\(74.\left(x-2\right)-2^3.3=2.5^2\Leftrightarrow74.\left(x-2\right)-8.3=2.25\)
\(\Leftrightarrow74.\left(x-2\right)-8.3=50\Leftrightarrow74.\left(x-2\right)-24=50\)
\(\Leftrightarrow74.\left(x-2\right)=50+24\Leftrightarrow74.\left(x-2\right)=74\)
\(\Leftrightarrow x-2=74:74\Leftrightarrow x-2=1\Leftrightarrow x=1+2\Leftrightarrow x=3\)
66 : ( 2x - 3 ) -22 =0
66 : ( 2x - 3 ) = 22
2x-3=66:22
2x-3=11
2x=11+3
2x=14
x=14:2
x=2