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a) \(\left(3x-3^4\right).7^5=3.7^7\)
\(3x-3^4=3.\left(7^7:7^5\right)\)
\(3x-3^4=3.7^2\)
\(3x-3^4=3.49\)
\(3x-81=147\)
\(3x=147+81\)
\(3x=228\)
\(x=228:3\)
\(x=76\)
b) \(4^{2x-5}-3.4^2=4^2\)
\(4^{2x-5}-3.16=16\)
\(4^{2x-5}-48=16\)
\(4^{2x-5}=16+48\)
\(4^{2x-5}=64\)
\(4^{2x-5}=4^3\)
\(2x-5=3\)
\(2x=3+5\)
\(2x=8\)
\(x=8:2\)
\(x=4\)
\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}-2.25=25.3\)
\(5^{2x-3}-50=75\)
\(5^{2x-3}=75+50\)
\(5^{2x-3}=125\)
\(5^{2x-3}=5^3\)
\(2x-3=3\)
\(2x=3+3\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
a,(3x-3^4).7^5=3.7^7 b,4^2x-3 -3.4^2=4^2 c,5^2x-3 -2.5^2=5^2.3
3x-3^4=(3.7^7):7^5 4^2x-3 -3.16=16 5^2x-3-2.25=25.3
3x-81=3.7^2 4^2x-3-48=16 5^2x-3-50=75
3x-81=3.49 4^2x-3=16+48 5^2x-3=75+50
3x-81=147 4^2x-3=64 5^2x-3=125
3x=147+81 4^2x-3=4^3 5^2x-3=5^3
3x=228 2x-3=3 2x-3=3
x=228:3 2x=3+3 2x=3+3
x=76 2x=6 2x=6
Vậy=76 x=6:2 x=6:2
x=3 x=3
Vậy x=3 Vậy x=3
52x-3 - 2.52 = 52.3
52x-3 = 52.3 + 52.2 = 52.(2+3)
52x-3 = 52.5 = 53
=> 2x - 3 = 3
=> 2x = 6
=> x = 3
a) \(2.5^2.3^2+\left\{\left[2.5^3-\left(5x+4\right).5\right]:\left(2^2.3.5\right)\right\}=453\)
\(2.25.9+\left\{\left[2.125-\left(5x+4\right).5\right]:\left(4.3.5\right)\right\}=453\)
\(50.9+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(450+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(\left[250-\left(5x+4\right).5\right]:60=453-450\)
\(\left[250-\left(5x+4\right).5\right]:60=3\)
\(250-\left(5x+4\right).5=3.60\)
\(250-\left(5x+4\right).5=180\)
\(\left(5x+4\right).5=250-180\)
\(\left(5x+4\right).5=70\)
\(5x+4=70:5\)
\(5x+4=14\)
\(5x=14-4\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
Vậy \(x=2\)
b) \(\left|x-\frac{1}{3}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=-2\\x-\frac{1}{3}=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\left(-2\right)+\frac{1}{3}\\x=2+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{7}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{7};\frac{7}{3}\right\}\)
a) 3^2x=9^2
3^2x=3^2.3^2
3^2x=3^4
3^2x=3^2.2
=>2x=2.2
=>x=4/2
=>x=2
\(5^{2x-3}-2=5^2.3:5^2\)
\(5^{2x-3}-2=3\)
\(5^{2x-3}=3+2\)
\(5^{2x-3}=5^1\)
=> 2x-3=1
2x=1+3
2x=4
x=4:2
x=2
Vậy x=2
\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}-2.25=25.3\)
\(5^{2x-3}-2.25=75\)
\(5^{2x-3}-2=75:25\)
\(5^{2x-3}-2=3\)
\(5^{2x-3}=3-2\)
\(5^{2x-3}=1\)
\(5^{2x-3}=5^0\)
\(\Rightarrow2x-3=0\)
\(2x=0+3\)
\(x=3:2\)
\(x=1.5\)
Vậy x = 1.5
\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^2.3+2.5^2\)
\(5^{2x-3}=5^2\left(2+3\right)\)
\(5^{2x-3}=5^3\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)
52x - 3 - 2 . 52 = 52 . 3
52x - 3 - 2 . 25 = 25 . 3
52x - 3 - 2 . 25 = 75
52x - 3 - 50 = 75
52x - 3 = 75 + 50
52x - 3 = 125
\(\Rightarrow\) 52x - 3 = 53
\(\Rightarrow\) 2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3.