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Đặt \(A=1.2.3+2.3.4+3.4.5+...+99.100.101\)
\(\Rightarrow4A=1.2.3.4+2.3.4.4+...+99.100.101.4\)
\(=1.2.3\left(4-0\right)+2.3.4\left(5-1\right)+...+99.100.101\left(102-98\right)\)
\(=\left(1.2.3.4+2.3.4.5+...+99.100+101.102\right)-\left(0.1.2.3+1.2.3.4+...+98.99.100.101\right)\)
\(=99.100.101.102-0.1.2.3\)
\(=101989800\)
\(\Rightarrow A=101989800:4=25497450\)
Vậy \(A=25497450.\)
Đặt A = 1.2.3 + 2.3.4 + ... + 99.100.101
=> 4A = 1.2.3.4 + 2.3.4.(5-1) + ... + 99.100.101.(102-98)
=> 4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + ... + 99.100.101.102 - 98.99.100.101
=> 4A = 99.100.101.102
=> 4A = 101989800
=> A = 25497450
1.2.3 = 1/4 . (1.2.3.4 - 0.1.2.3)
2.3.4 = 1/4 . (2.3.4.5 - 1.2.3.4)
3.4.5 = 1/4 . (3.4.5.6 - 2.3.4.5)
.................
99.100.101 = 1/4 . (99.100.101.102 - 98.99.100.101)
C = 1.2.3+2.3.4+3.4.5+.........+99.100.101
C= 1/4 . (99.100.101.102 - 98.99.100.101)
CHUC BN HOK GIỎI!
\(A=1.2.3+2.3.4+...+99.100.101\)
\(\Rightarrow4A=1.2.3.4+2.3.4\left(5-1\right)+...+99.100.101.\left(102-98\right)\)
\(=1.2.3.4+2.3.4.5-1.2.3.4+...+99.100.101.102-98.99.100.101\)
\(=99.100.101.102\)
\(\Rightarrow A=\dfrac{99.100.101.102}{4}=99.25.101.102\)
Vậy...
Đặt \(C=1.2.3+2.3.4+3.4.5+...+99.100.101\)
\(4C=1.2.3.4+2.3.4.4+3.4.5.4+...+99.100.101.4\)
\(4C=1.2.3.\left(4-0\right)+2.3.4.\left(5-1\right)+3.4.5.\left(6-2\right)+....+99.100.101.\left(102-98\right)\)
\(4C=1.2.3.4+2.3.4.5+3.4.5.6+...+99.100.101.102\)
\(4C=99.100.101.102=101989800\)
\(\Rightarrow C=\frac{101989800}{4}=25497450\)
A=1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100
4A=(1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100).4
4A=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+4.5.6(7-3)+...+98.99.100(101-97)
4A=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+4.5.6.7-3.4.5.6+...+98.99.100.101-97.98.99.100
4A=1.2.3.4-1.2.3.4+2.3.4.5-2.3.4.5+3.4.5.6-3.4.5.6+...+97.98.99.100-97.98.99.100+98.99.100.101
4A=98.99.100.101
A=98.99.100.101/4
Nhân 4 p lên rồi trừ đi p còn 3 p là xong
Dễ mà ~ Suy nghĩ đi ~~~