Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 6:
c: \(9x^2+6x+1=\left(3x+1\right)^2\)
d: \(4x^2-9=\left(2x-3\right)\left(2x+3\right)\)
e: \(x^3+27=\left(x+3\right)\left(x^2-3x+9\right)\)
(x-1)(x+1)(x+2)
=(x^2-1)(x+2)
=x^3+2x^2-x-2
[X-1/2] [X+1/2] [4X-1]
=\(\left(x^2-\frac{1}{4}\right)\left(4x-1\right)\)
=\(4x^3-x^2-x+\frac{1}{4}\)
1/2X2Y2 [2X+Y] [2X-Y]
=\(\frac{1}{2}x^2y^2\left(4x^2-y^2\right)\)
=\(2x^2y^2-\frac{1}{2}x^2y^4\)
a. 2x^2 ( 5x^3 - 4x^2 - 7xy + 1 )
= 10x^5 - 8x^4 - 14x^3y + 1
b. ( x - 5 ) ( x + 3 )
= x^2 + 3x - 5x - 15
= x^2 - 2x - 15
c. ( x - 1 ) ( x + 2 )
= x^2 + 2x - x - 2
= x^2 - x - 2
d. ( 2x + y ) ( 2x - y )
= 4x^2 - 2xy + 2xy - y^2
= 4x^2 - y^2
a) \(2x^2\left(5x^3-4x^2.g-7xy+1\right)\)
\(=10x^5-8x^4.g-14x^3y+2x^2\)
b) \(\left(x-5\right)\left(x+3\right)\)
\(=x^2+3x-5x-15\)
\(=x^2-2x-15\)
c) \(\left(x-1\right)\left(x+2\right)\)
\(=x^2+2x-x-2\)
\(=x^2+x-2\)
d) \(\left(2x+y\right)\left(2x-y\right)\)
\(=4x^2-y^2\)
Bài 1:
a: Ta có: \(\left(6x+3\right)-\left(2x-5\right)\left(2x+1\right)\)
\(=\left(2x+1\right)\left(3-2x+5\right)\)
\(=\left(2x+1\right)\left(8-2x\right)\)
\(=2\left(4-x\right)\left(2x+1\right)\)
b) Ta có: \(\left(3x-2\right)\left(4x-3\right)-\left(2-3x\right)\left(x-1\right)-2\left(3x-2\right)\left(x+1\right)\)
\(=\left(3x-2\right)\left(4x-3\right)+\left(3x-2\right)\left(x-1\right)-\left(3x-2\right)\left(2x+2\right)\)
\(=\left(3x-2\right)\left(4x-3+x-1-2x-2\right)\)
\(=\left(3x-2\right)\left(3x-6\right)\)
\(=3\left(3x-2\right)\left(x-2\right)\)
Bài 2:
a: Ta có: \(\left(a-b\right)\left(a+2b\right)-\left(b-a\right)\left(2a-b\right)-\left(a-b\right)\left(a+3b\right)\)
\(=\left(a-b\right)\left(a+2b\right)+\left(a-b\right)\left(2a-b\right)-\left(a-b\right)\left(a+3b\right)\)
\(=\left(a-b\right)\left(a+2b+2a-b-a-3b\right)\)
\(=\left(a-b\right)\left(2a-4b\right)\)
\(=2\left(a-b\right)\left(a-2b\right)\)
f: Ta có: \(x^2-6xy+9y^2+4x-12y\)
\(=\left(x-3y\right)^2+4\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x-3y+4\right)\)
a. = x2(3x-2y)
b. = x(x - y) + (y - x)
= x(x - y) - (x - y)
= (x - 1)(x - y)
\(\frac{1}{2}\) x2.y2.(4x2-y2)
=2x4y2-1/2x2y4