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Giải:
a) \(2\dfrac{17}{20}-1\dfrac{15}{11}+6\dfrac{9}{20}:3\)
\(=\dfrac{57}{20}-\dfrac{26}{11}+\dfrac{129}{20}:3\)
\(=\dfrac{107}{220}+\dfrac{43}{20}\)
\(=\dfrac{29}{11}\)
b) \(4\dfrac{3}{7}:\left(\dfrac{7}{5}.4\dfrac{3}{7}\right)\)
\(=\dfrac{31}{7}:\left(\dfrac{7}{5}.\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}\)
\(=\dfrac{5}{7}\)
c) \(\left(3\dfrac{2}{9}.\dfrac{15}{23}.1\dfrac{7}{29}\right):\dfrac{5}{23}\)
\(=\left(\dfrac{29}{9}.\dfrac{15}{23}.\dfrac{36}{29}\right):\dfrac{5}{23}\)
\(=\dfrac{60}{23}:\dfrac{5}{23}\)
\(=12\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
\(4\times\left(x+5\right)^3-7=101\)
\(\Rightarrow4\times\left(x+5\right)^3=101+7\)
\(\Rightarrow4\times\left(x+5\right)^3=108\)
\(\Rightarrow\left(x+5\right)^3=108\div4\)
\(\Rightarrow\left(x+5\right)^3=27\)
\(\Rightarrow\left(x+5\right)^3=3^3\)
\(\Rightarrow x+5=3\)
\(\Rightarrow x=3-5\)
\(\Rightarrow x=-2\)
Keuka
4(x+5)3-7=101
4(x+5)3=101+7
4(x+5)3=108
(x+5)3=108:4
(x+5)3=27
(x+5)3=33
=> x+5=3
x=3-5
x=-2
Vậy x=-2
\(\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}\)
\(=\dfrac{67}{9}+\dfrac{51}{11}-\dfrac{31}{9}\)
\(=\dfrac{67}{9}-\dfrac{31}{9}+\dfrac{51}{11}\)
\(=4+\dfrac{51}{11}\)
\(=\dfrac{95}{11}\)
Chúc bạn học tốt
<=> \(\frac{x}{3}+\frac{2}{3}+x=\frac{4}{7}\)
<=>\(\frac{4x}{3}=-\frac{2}{21}\)
<=>x\(-\frac{1}{14}\)
4-(7-x)=x-(13-4)
<=> 4-7+x=x-13+4
<=> x-3=x-9
<=> x-x=-9 -3
<=> 0=-12 (Vô lí)
Vậy không có giá trị nào của x thoả mãn đề bài
Thank bạn!!!