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Ta có\(7^{14}< 8^{14}=2^{42}< 2^{55}=32^{11}\)
Vậy\(7^{14}< 32^{11}\)
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( 2x + 2x + 2x + ... + 2x + 2x ) + ( 1 + 2 + ... + 2015 ) = 0
4030x + 2031120 = 0
4030x = - 2031120
x = - 2031120 : 4030
x = - 504
vậy x = -504
(2x+1)+(2x+2)+.......+(2x+2015)=0
<=>2x+1+2x+2+2x+3+...+2x+2015=0
<=>(2x+2x+2x+2x+2x+2x+....+2x)+(1+2+3+4+5+....+2015)=0
<=>2x.2015+2031120=0
<=>4030x+2031120=0
<=>4030x= -2031120
<=>x=-2031120:4030=-504
Vậy x=-504
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Vì x-5 chia hết cho 2x-1
=> (x-5):(2x-1)=1
x-5=1.(2x-1)=2x-1
x+(-5)=2x+(-1)
x+(-5)-2x=-1
(-1).x+(-5)=-1
(-1).x=(-1)-(-5)=4
x=4:(-1)=-4
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=>\(\orbr{\begin{cases}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{cases}}\)
+, x+\(\frac{1}{2}\)=0 +,\(\frac{2}{3}-2x=0\)
x=\(-\frac{1}{2}\) =>\(\frac{2}{3}=2x\)
=>\(x=\frac{1}{3}\)
Vậy........
\(2x:32=0\)
\(2x=0\times32\)
\(2x=0\)
\(x=0:2\)
\(\Rightarrow x=0\)
2x=0.32=0
x=0:2
x=0