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-5.(x+1/5) -1/2.(x-2/3)=3/2x-5/6
-5x + (-1) -1/2x -1/3=3/2x-5/6
-5x-1/2x-3/2x=1+1/3-5/6
x.(-5-1/2-3/2)= 6/6+2/6+(-5/6)
x.(-10/2+(-1/2)+(-3/2))=3/6
x.6/2=1/2
x=1/2:6/2
x=1/6
Vậy x = 1/6
\(\frac{2}{6}+\frac{2}{12}+...+\frac{2}{x.\left(x+1\right)}=\frac{2011}{2013}\)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{2011}{2013}:2\)
\(\frac{1}{2}-\frac{1}{x+1}=\frac{2011}{4026}\)
\(\frac{\left(x+1-2\right)}{2.\left(x+1\right)}=\frac{2011}{4026}\)
Tim x biet
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2019}{2020}\)
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2019}{2020}\)
=> \(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x\left(x+1\right)}=\frac{2019}{2020}\)
=> \(2\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{2019}{2020}\)
=> \(2\left(\frac{1}{2}-\frac{1}{x+1}\right)=\frac{2019}{2020}\)
=> \(1-\frac{2}{x+1}=\frac{2019}{2020}\)
=> \(\frac{2}{x+1}=\frac{1}{2020}=\frac{2}{4040}\)
=> x + 1 = 4040 => x = 4039
\(\frac{2}{6}+\frac{2}{12}+...+\frac{2}{x\left(x-1\right)}=\frac{2007}{2009}\)
\(2\cdot\left(\frac{1}{6}+\frac{1}{12}+..+\frac{1}{x\left(x-1\right)}\right)=\frac{2007}{2009}\)
\(\frac{1}{6}+\frac{1}{12}+..+\frac{1}{x\left(x-1\right)}=\frac{2007}{2009}:2\)
\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{\left(x-1\right)x}=\frac{2007}{4018}\)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+..+\frac{1}{x-1}-\frac{1}{x}=\frac{2007}{4018}\)
\(\frac{1}{2}-\frac{1}{x}=\frac{2007}{4018}\)
\(\frac{1}{x}=\frac{1}{2}-\frac{2007}{4018}\)
\(\frac{1}{x}=\frac{1}{2009}\)
=> x = 2009
1/3+1/6+.......+2/x(x+1)=2014/2015
=>1x2/3x2+1x2/6x2+.....+2/x(x+1)=2014/2015
=>2/6+2/12+...........+2/x(x+1)=2014/2015
=>2(1/6+1/12+......+1/x(x+1)=2014/2015
=>2(1/2x3+1/3x4+.....+1/x(x+1)=2014/2015
=>2(1/2-1/3+1/3-1/4+.....+1/x-1/x+1=2014/2015
=>2(1/2-1/x+1)=2014/2015
=>1/2-1/x+1=2014/2015:2
=>1/2-1/x+1=1007/2015
=>1/x+1=1/2-1007/2015
=>1/x+1=1/4030
=>x+1=4030
=>x=4030-1
=>x=4029
Quy đồng lên nhé, Nhân với 2
= 2/6 + 2/12 + 2/20 +......+ 2/x(x+1)= 2014/ 2015
= 2 (1/(2.3) + 1/(3.4) + .... + 1/ x.(x+1) ) = 2014 / 2015
Tự làm nốt
\(\frac{x+1}{x-2}=\frac{3}{4}\)
\(\Rightarrow4x+4=3x-6\)
\(x=-10\)
---------------------------------------------------
\(\frac{x-1}{x+1}=\frac{x}{x-2}\)
\(\Rightarrow\left(x-1\right)\left(x-2\right)=x\left(x+1\right)\)
\(x^2-x-2x+2=x^2+x\)
\(4x=2\)
\(x=\frac{1}{2}\)
NHANH HO MINH VI DAY LA DE CUONG TOAN
giup minh voi!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!