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\(\frac{2006\times2007-2593}{2005\times2006+1419}=\frac{2005\times2006+2\times2006-2593}{2005\times2006+1419}\)
\(=\frac{2005\times2006+4012-2593}{2005\times2006+1419}=\frac{2005\times2006+1419}{2005\times2016+1419}=1\)
2006 * ( 2005 + 2 ) - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 2006 * 2 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 4012 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 1419 / 2005 * 2006 + 1419 = 1
k cho tui nha
y=\(\frac{2006x2005-1}{2004x2006+2005}=\frac{2006x2005-1}{\left(2005-1\right)x2006+2005}=\frac{2006x2005-1}{2005x2006-2006+2005}=\frac{2006x2005-1}{2005x2006-1}=1\)
\(\frac{1999}{2004}+\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\)
=\(\left(\frac{1999}{2004}+\frac{5}{2004}\right)+\left(\frac{2001}{2005}+\frac{4}{2005}\right)\)
=\(1+1\)
=2
\(\frac{1999}{2004}+\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\) = \(\frac{1999}{2004}+\frac{5}{2004}+\frac{2001}{2005}+\frac{4}{2005}\)
= \(1+1\)
= \(2\)
Click mik nha !!!!!!!!!!!!!!!!!!!
\(B=\frac{2003+2004}{2004+2005}=\frac{2003}{2004+2005}+\frac{2004}{2004+2005}\)
Ta có: \(\frac{2003}{2004}>\frac{2003}{2004+2005}\)
\(\frac{2004}{2005}>\frac{2004}{2004+2005}\)
\(\frac{2003}{2004}+\frac{2004}{2005}>\frac{2003+2004}{2004+2005}\)
\(A>B\)
Vậy A>B
\(=\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}=\frac{2005\times2006+2005\times1-1}{2004+2005\times2006}=\frac{2005\times2006+2004}{2004+2005\times2006}=1\)