Question

[Hoang Duc Thinh]

\(\frac{1}{4}\times\frac{2}{6}\times\frac{3}{8}\times...\times\frac{30}{62}\times\frac{31}{64}\)

Answer 1

[Nguyễn Ngọc Anh Minh]

\(=\frac{1x2x3x...x30x31}{2^{31}x\left(2x3x4x...x31x32\right)}=\frac{1}{2^{31}x32}=\frac{1}{2^{36}}\)