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Phan Hoàng Mai
Tính :
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right).\frac{3}{8}-72:12^2\)
\(=\left(-\frac{5}{10}-\frac{3}{5}\right):\frac{-22}{25}+\left(\frac{2}{25}-\frac{108}{100}\right).\frac{3}{8}-72:144\)
\(=\left(-\frac{5}{10}-\frac{6}{10}\right).\frac{-25}{22}+\left(\frac{8}{100}-\frac{108}{100}\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{-11}{10}.\frac{-25}{22}+\left(-1\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{\left(-11\right).\left(-25\right)}{10.22}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{5}{4}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{10}{8}+\frac{-3}{8}-\frac{4}{8}\)
\(=\frac{3}{8}\)
Chúc bạn học tốt!!!
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\cdot\frac{3}{8}-72:12^2\)
=\(\left(-\frac{1}{2}-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-\frac{27}{25}\right)\cdot\frac{3}{8}-\frac{72}{144}\)
=\(\left(-\frac{11}{10}.\left(-\frac{25}{22}\right)\right)-1\cdot\frac{3}{8}-\frac{1}{2}\)
= \(\frac{5}{4}-\frac{3}{8}-\frac{1}{2}\)
= \(\frac{10}{8}-\frac{3}{8}-\frac{4}{8}=\frac{3}{8}\)
\(\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2\)
\(=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}\)
\(=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}\)
\(=\dfrac{3}{8}\)
\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\)
\(\left(\frac{12}{25}\right)^x=\frac{144}{625}\)
\(\left(\frac{12}{25}\right)^x=\left(\frac{12}{25}\right)^2\)
\(x=2\)
Chúc bạn học tốt ^^
\(\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^{2019}}{\left(\frac{2}{5}\right)^2.\left(\frac{-5}{12}\right)^3}:\sqrt{\frac{9}{25}}\)\(=\frac{\frac{2^3}{3^3}.\frac{-3^2}{4^2}.\left(-1\right)}{\frac{2^2}{5^2}.\frac{-5^3}{12^3}}:\frac{3}{5}\)
\(=\frac{\frac{2^3}{5^3}.\frac{-3^2}{2^4}.\left(-1\right)}{\frac{2^2}{5^2}.\frac{-5^3}{2^6.3^3}}:\frac{3}{5}=\frac{\frac{-1}{3.2}}{\frac{-5}{2^4.3^3}}:\frac{3}{5}\)\(=\frac{-1}{3.2}.\frac{-2^4.3^3}{5}.\frac{5}{3}\)
\(=\frac{2^3.3^2}{5}.\frac{5}{3}=24\)
\(=\left(25+\dfrac{12}{67}+9+\dfrac{13}{41}-8-\dfrac{12}{67}+3+\dfrac{28}{41}\right)\cdot\dfrac{-21}{13}\)
\(=\left(25+9-8+3+1\right)\cdot\dfrac{-21}{13}=\dfrac{-630}{13}\)
=\(\frac{12}{25}.\left(-38,2-61,8\right)\)
=\(\frac{12}{25}.\left(-100\right)\)
=\(-48\)
= 12/25 . (-38,2 - 61,8)
= 12/25 . (-100)
= -48