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![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3:
a: \(7_{10}=111_2\)
\(22_{10}=10110_2\)
\(97_{10}=\text{1100001}_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(23_{10}=\text{10111}_2=17_{16}\)
\(54_{10}=\text{110110}_2=36_{16}\)
\(121_{10}=\text{1111001}_2=79_{16}\)
\(95_{10}=\text{1011111}_2=5F_{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(1CA_{16}=458_{10}=\text{111001010}_2\)
b: \(1101_2=13_{10}=D_{16}\)
c: \(998_{10}=3E6_{16}\)
d: \(67_{10}=\text{1000011}_2\)
e: \(1111001_{10}=10F3D9_{16}\)
a) 1CA(16)=458(10)=111001010(2)
b)1101(2)=13 (10)=D (16)
c)998(10)=3E6(16)
d)67(10)=1000011(2)
e)1111001(10)=10F3D9(16)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(1CA_{16}=458_{10}=\text{111001010}_2\)
b: \(1101_2=13_{10}=D_{16}\)
c: \(998_{10}=3E6_{16}\)
d: \(67_{10}=\text{1000011}_2\)
e: \(1111001_{10}=10F3D9_{16}\)
a) 1CA(16)=458(10)=111001010(2)
b)1101(2)=13 (10)=D (16)
c)998(10)=3E6(16)
d)67(10)=1000011(2)
e)1111001(10)=10F3D9(16)
5D1616 -> 5.163+13.162+1.161+6.160 = 2383010
7D71616 -> 7.164+13.163+7.162+1.161+6.160 = 51381410
1111112 -> 1.25+1.24+1.23+1.22+1.21+1.20 = 6310
101101012 -> 1.27+0.26+1.25+1.24+0.23+1.22+0.21+1.20 = 18110