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\(1+\dfrac{1}{2}.\dfrac{3.2}{2}+\dfrac{1}{3}.\dfrac{4.3}{2}+...+\dfrac{1}{500}.\dfrac{501.500}{2}\)
\(=\dfrac{2}{2}+\dfrac{3}{2}+\dfrac{4}{2}+...+\dfrac{501}{2}\)
\(=\dfrac{2+3+4+...+501}{2}\)
\(=\dfrac{\left(501-2+1\right).\left(501+2\right)}{4}\)
\(=\dfrac{\left(501-2+1\right).\left(501+2\right)}{4}=62875\)
\(B=\dfrac{\dfrac{2}{3}\left(\dfrac{17}{3}-\dfrac{4}{13}\right)+\dfrac{7}{3}}{\dfrac{9}{20}}=3:\dfrac{9}{20}=3\cdot\dfrac{20}{9}=\dfrac{60}{9}=\dfrac{20}{3}\)
Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
\(C=\dfrac{-5}{7}+\dfrac{-2}{7}+\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{-1}{5}=-1+1-\dfrac{1}{5}=\dfrac{-1}{5}\)
\(m=\dfrac{2^7\cdot3^5+2^4\cdot3^9}{2^6\cdot3^5+2^3\cdot3^9}\)
\(m=\dfrac{2^4\cdot3^5\cdot\left(2^3+3^4\right)}{2^3\cdot3^5\cdot\left(2^3+3^4\right)}\)
\(m=\dfrac{2^4\cdot3^5}{2^3\cdot3^5}\)
\(m=\dfrac{2^4}{2^3}\)
\(m=2^{4-3}\)
\(m=2\)
1.43x7/31x7=301/217
59x13/7x13=767/217
=>767/217>301/217
hay59/13>43/31
2.rút gọn -48/224 còn -3/14
rút gọn -52/247 còn -4/19
-3/14=-3x19/14x19=-57/266
-4/19=-4x14/19x14=-56/266
=>-57/266<-56/266
hay-48/244<-52/247
vậy...
Bạn học lớp nào trường gì mà bt về nhà môn Toán giống của bọn mik zậy ?
\(\dfrac{2^6.18+2^7}{2^6.5^2-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6.\left(5^2-3\right)}=\dfrac{20}{5^2-3}=\dfrac{20}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)
\(=\dfrac{2^6.18+2^6.2}{2^6.25-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6\left(25-3\right)}=\dfrac{18+2}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)