Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
f(x) + g(x)
= (x5 - 3x2 + 7x4 - 9x3 + x2 - 1/4x) + (5x4 - x5 +x2 - 2x3 + 3x2 - 1/4)
= x5 - 3x2 + 7x4 - 9x3 + x2 - 1/4x + 5x4 - x5 +x2 - 2x3 + 3x2 - 1/4
=12x4 - 11x3 + 2x2 - 1/4x - 1/4
f(x) - g(x)
= (x5 - 3x2 + 7x4 - 9x3 + x2 - 1/4x) - (5x4 - x5 +x2 - 2x3 + 3x2 - 1/4)
= = x5 - 3x2 + 7x4 - 9x3 + x2 - 1/4x - 5x4 + x5 - x2 + 2x3 - 3x2 + 1/4
= 2x5 + 2x4 - 7x3 - 6x2 - 1/4x + 1/4
Thay x= -1/2 vào A:
\(A=3\left|-\frac{1}{2}\right|^2-4\left|-\frac{1}{2}\right|+5\)
\(=\frac{3}{4}-2+5\)
\(=3,75\)
Thay x=4 vào B:
\(B=2\left|4-2\right|+3\left|1-4\right|\)
\(=2\cdot2+3\cdot3\)
\(=10\)
---------------
|x| = 1/2 => x= +- 1/2
Th1: x=-1/2
Thay x=-1/2 vào C:
\(C=\frac{5\left(-\frac{1}{2}\right)^2-7\cdot\left(-\frac{1}{2}\right)+1}{3\cdot\left(-\frac{1}{2}\right)-1}\)
\(=\frac{\frac{5}{4}+\frac{7}{2}+1}{-\frac{3}{2}-1}\)
\(=\frac{23}{4}:\left(-\frac{5}{2}\right)\)
\(=-\frac{23}{10}\)
Th2: x=1/2
Thay x=1/2 vào C:
\(C=\frac{5\cdot\frac{1}{2}^2-7\cdot\frac{1}{2}+1}{3\cdot\frac{1}{2}-1}\)
\(=\frac{\frac{5}{4}-\frac{7}{2}+1}{\frac{3}{2}-1}\)
\(=\left(-\frac{5}{4}\right):\frac{1}{2}\)
\(=-\frac{5}{2}\)
1
2(\(\frac{3}{4}\)-5x)=\(\frac{4}{5}\)-3x
=> \(\frac{6}{4}-10x=\frac{4}{5}-3x\)
=>\(-10x+3x=\frac{4}{5}-\frac{6}{4}\)
=> \(x=\frac{1}{10}\)
2 .
\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
=>\(\frac{3}{2}-1+4x=\frac{2}{3}-7x\)
=>\(11x=\frac{1}{6}\)
=>x=\(\frac{1}{66}\)
3.
\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
=>\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)
=>\(-2x=\frac{-2}{3}\)
=>\(\frac{1}{3}\)
4. câu 4 ko hiểu bạn ơi
a) Ta có: \(5x\left(\frac{1}{5}x-2\right)+3\left(6-\frac{1}{3}x^2\right)=12\)
\(\Leftrightarrow x^2-10x+18-x^2=12\)
\(\Leftrightarrow-10x+18=12\)
\(\Leftrightarrow-10x=-6\)
hay \(x=\frac{3}{5}\)
Vậy: \(x=\frac{3}{5}\)
b) Ta có: \(7x\left(x-2\right)-5\left(x-1\right)=7x^2+3\)
\(\Leftrightarrow7x^2-14x-5x+5-7x^2-3=0\)
\(\Leftrightarrow-19x+2=0\)
\(\Leftrightarrow-19x=-2\)
hay \(x=\frac{2}{19}\)
Vậy: \(x=\frac{2}{19}\)
1,\(2\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
\(\frac{6}{4}-10x=\frac{4}{5}-3x\)
\(\frac{6}{4}+\frac{4}{5}=7x\)
\(\frac{23}{10}=7x\)
\(\frac{23}{70}=x\)
2,\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
\(\frac{3}{2}-1-4x=\frac{2}{3}-7x\)
\(\frac{3}{2}-1-\frac{2}{3}=-3x\)
\(\frac{-1}{6}=-3x\)
\(\frac{1}{18}=x\)
3,\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)
\(\frac{3}{2}-\frac{7}{6}+\frac{1}{3}=2x\)
\(\frac{2}{3}=2x\)
\(\frac{1}{3}=x\)
4,mình không hiểu a ở đây là gì
bài 1
a) \(-\frac{1}{3}xy\).(3\(x^2yz^2\))
=\(\left(-\frac{1}{3}.3\right)\).\(\left(x.x^2\right)\).(y.y).\(z^2\)
=\(-x^3\).\(y^2z^2\)
b)-54\(y^2\).b.x
=(-54.b).\(y^2x\)
=-54b\(y^2x\)
c) -2.\(x^2y.\left(\frac{1}{2}\right)^2.x.\left(y^2.x\right)^3\)
=\(-2x^2y.\frac{1}{4}.x.y^6.x^3\)
=\(\left(-2.\frac{1}{4}\right).\left(x^2.x.x^3\right).\left(y.y^2\right)\)
=\(\frac{-1}{2}x^6y^3\)
Bài 3:
a) \(f\left(x\right)=-15x^2+5x^4-4x^2+8x^2-9x^3-x^4+15-7x^3\)
\(f\left(x\right)=\left(5x^4-x^4\right)-\left(9x^3+7x^3\right)-\left(15x^2+4x^2-8x^2\right)+15\)
\(f\left(x\right)=4x^4-16x^3-11x^2+15\)
b)
\(f\left(x\right)=4x^4-16x^3-11x^2+15\)
\(f\left(1\right)=4\cdot1^4-16\cdot1^3-11\cdot1^2+15\)
\(f\left(1\right)=4\cdot1^4-16\cdot1^3-11\cdot1^2+15\)
\(f\left(1\right)=-8\)
\(f\left(x\right)=4x^4-16x^3-11x^2+15\)
\(f\left(-1\right)=4\cdot\left(-1\right)^4-16\cdot\left(-1\right)^3-11\cdot\left(-1\right)^2+15\)
\(f\left(-1\right)=24\)
Nếu \(x=\frac{1}{2}\Rightarrow S=-2\)
\(x=\frac{-1}{2}\Rightarrow S=\frac{-14}{5}\)
Nhớ k đúng nhé !
Chúc các bạn học tốt !!!!
Vì | x| = 1/2 suy ra x = 1/2 hoặc x=- 1/2
* Tại x = 1/2:Thay x = 1/2 vào S ta có: S=\(\frac{5\cdot\left(\frac{1}{2}\right)^2-7\cdot\frac{1}{2}+1}{3\cdot\left(\frac{1}{2}\right)-1}=\frac{5\cdot\frac{1}{4}-\frac{7}{2}+1}{\frac{3}{2}-1}=-\frac{5}{4}\cdot2=-\frac{5}{2}\)
* Tại x= - 1/2: Thay x= - 1/2 vào S ta có: S=\(\frac{5\cdot\left(-\frac{1}{2}\right)^2-7\left(-\frac{1}{2}\right)+1}{3\cdot\left(-\frac{1}{2}\right)-1}=\frac{5\left(\frac{1}{4}\right)+\frac{7}{2}+1}{-\frac{3}{2}-1}=\frac{23}{4}\cdot\left(-\frac{2}{5}\right)=-\frac{23}{10}\)